Schrodinger developed a famous equation that allows the solutions for electron wave functions to be found given a specific potential. For the case of an atom, Schroginger's equation allows the determination of electron wave functions. These wave functions tell us how electrons are distributed in space around the atom.
Answer:
60%
Explanation:
M(NH4NO3) = 2*14 +4*1 +3*16 = 80 g/mol
M(3O) = 3*16 = 48 g/mol
(48/80) *100 % =60% oxygen by mass.
Answer:
Pb(NO3)2 + 2NaCl = 2NaNO3 + PbCl2
Answer:
Subtract water vapor pressure from total pressure to get partial pressure of gas A: PA=1.03 atm- 1 atm=0.03 atm.
What is the total pressure of the gases at 298 K?
98.8 kPa
A sample of nitrogen gas is bubbled through water at 298 K and the volume collected is 250 mL. The total pressure of the gas, which is saturated with water vapour, is found to be 98.8 kPa at 298 K.
The total pressure of a mixture of gases can be defined as the sum of the pressures of each individual gas: Ptotal=P1+P2+… +Pn. + P n . The partial pressure of an individual gas is equal to the total pressure multiplied by the mole fraction of that gas.
How do you find the partial pressure of water in air?
e is vapor pressure Rv = R∗/Mv = 461.5Jkg−1K−1 and Mv = 18.01gmol−1, ϵ = Mv/Md = 0.622. The vapor pressure is the partial pressure of the water vapor. where es is in Pascals and T is in Celsius.
ExpHow do you find the pressure of h2?
For the high pressures in which hydrogen gas is often stored, the van der Waals equation can be used. It is P+a(n/V)^2=nRT. For diatomic hydrogen gas, a=0.244atm L^2/mol^2 and b=0.0266L/mol.lanation:
Answer:
pOH = 5.961
Explanation:
To find the pH of a weak base we can use Henderson-Hasselbalch equation for weak bases:
pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]
<em>Where pKb is -log Kb = 4.187 and [] could be taken as moles of each specie.</em>
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<em>Moles (CH₃)₃NHCl:</em>
0.0441L * (0.15mol/L) = 6.615x10⁻³moles
<em>Moles (CH₃)₃N:</em>
0.0233L * (0.16mol/L) = 3.728x10⁻³moles
And pOH is:
pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]
pOH = 4.187 + log [6.615x10⁻³moles] / [3.728x10⁻³moles]
<h3>pOH = 5.961</h3>
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