Answer:
The answers are in the explanation
Explanation:
For the equilibrium:
B(aq) + H₂O(l) ⇌ HB⁺(aq) + OH⁻(aq).
By LeChatelier's principle, the increase in the concentration of a reactant (for example) at equilibrium will change the system counteracting the increasing producing more product.
Thus,
A) Will the equilibrium constant for the reaction increase, decrease, or stay the same? Why?
.
The equilibrium constant is a thermodynamic constant that stay the same with the addition of a compound.
B) Will the concentration of HB⁺(aq) increase, decrease, or stay the same? Why?
By LeChatelier's principle, the addition of B will induce the formation of more HB⁺(aq) increasing the concentration.
C) Will the pH of the solution increase, decrease, or stay the same? Why?
As the addition of B induce the increasing of OH⁻, the pH of the solution will increase.
I hope it helps!
Answer:
We need 113000 J of heat (option 2 is correct)
Explanation:
Step 1: Data given
Mass of liquid water = 50.0 grams
ΔHVap = 2260 J/g
Temperature = 100 °C
ΔHVap = The amount of heat released to change phase of a liquid water to steam = 2260 J/g
Step 2: Calculate the heat needed
Q =m* ΔHVap
⇒with Q = the amount of heat needed = TO BE DETERMINED
⇒with m = the mass of water = 50.0 grams
⇒with ΔHVap = 2260 J/g
Q = 50.0 grams * 2260 J
Q = 113000 J
We need 113000 J of heat (option 2 is correct)
Answer:
mass molar of gas (Mw):
Mw = 107 g/mol
Explanation:
∴ m gas = 3.82 g
∴ V gas = 0.854 L
∴ T = 302 K
∴ P = 1.04 atm
ideal gas:
∴ n = m / Mw
⇒ PV = RTm/Mw
⇒ Mw = RTm / PV
⇒ Mw = ((0.082 atm.L/K.mol)*(302 K)*(3.82 g)) / ((1.04 atm)*(0.854 L)
⇒ Mw = 106.51 g/mol ≅ 107 g/mol
