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gogolik [260]
3 years ago
8

PLEASE HELP

Chemistry
1 answer:
WITCHER [35]3 years ago
4 0
The right answer is high number of offspring produced. asexual reproduction only requires on orgainism and creates an identical copy leaving no room for an increase of intelligence. plus it creates much more offspring and more often than sexual reproduction.
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Explain how the equation for GPE = force x distance.
Mkey [24]
GPE is the gravitational Potential Energy which is given by mgh.

mg is the gravitational force(a force) and h is the height of the object(or distance of the object from earth's surface)

SO GPE = mg (force) x h (distance)
4 0
4 years ago
When the valve between the two containers is opened and the gases allowed to mix, how does the volume occupied by the n2 gas cha
schepotkina [342]
Missing question: 
Nitrogen: <span>2.0 L; </span>1.0 atm; 25°<span>C.
Oxygen: 3</span>.0 L; 2.0 atm; 25°C.
<span>When the valve between the two containers is opened, nitrogen gas moves from one container to another container and gases are mixed together, total volume of nitrogen is than:
V(nitrogen) = 2,0 L + 3,0 L = 5,0 L.</span>
4 0
3 years ago
Read 2 more answers
PLS HELP!! it’s science how do waves travel through gas
HACTEHA [7]

By 'waves' do you mean sound waves? If so sound waves need to travel through things like solids, liquids and yup <u>gases. </u>When the waves travel they are vibrating the molecules in the matter. By doing this he molecules in solids are packed very tightly.

6 0
3 years ago
Solve the following problem and round the correct number of significant
RUDIKE [14]

Answer:

4.5 + 2.34 = 6.8

Sig Figs:

2

Decimals:

1

Scientific Notation:

6.8 × 10ⁿ

Words:

six point eight

5 0
3 years ago
Consider a solution containing .100 M fluoride ions and .126M hydrogen fluoride. The concentration of fluoride ions after the ad
S_A_V [24]
Given:

Concentration of Fluoride ions = 0.100 M
Concentration of Hydrogen Fluoride = 0.126 M

Asked: Concentration of fluoride ions after the addition of 5ml of 0.0100 M HCl to 25 mL of the solution

Assume: 50:50 ratio of fluoride ions and HF

12.5ml*0.1mol/L *1L/1000mL + 12.5*0.126mol/L * 1L/1000mL = 2.825x10^-3 moles F-

5ml * 0.01 mol/L *1L/1000mL = 5x10^-5 moles

Assume: Volume additive

Final concentration = 2.825x10^-3 + 5x10^-5 moles/ 30 ml * 1000ml/L =0.0958 M
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3 0
3 years ago
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