<span>The acrylic plastic rod is 200 mm long and 15 mm in
diameter. If an axial load of 300 N is applied to it, determine
the change in its length and the change in its diameter.
. latd = -0.0002515 (15) = -0.00377 mm
elat = -Velong = -0.4(0.0006288) = -0.0002515
d = elong L = 0.0006288 (200) = 0.126 mm
elong = s
E = 1.697(106
)
2.70(109
) = 0.0006288
s = P
A = 300 p
4 (0.015)2 = 1.697 MPa
•3–25. T</span>
- The bullet can travel about distance of (2115 m)
- Velocity can be regarded as the ratio of distance to time
- Velocity= (distance / time)
Given: velocity= 450 m/s
Time= 4.7s
- Distance= ( velocity × time)
<em>If we substitute the values</em>
= 2115 m
Therefore, the bullet can travel about 2115 m
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Answer:
C. greater than D, but less than 2D
Explanation:
The amount of potential energy in the system is a function of the compression of the spring. That is the same for both masses.
The potential energy is transferred to kinetic energy when the spring is released. The kinetic energy is jointly proportional to the mass and the square of the velocity. That is, the velocity is inversely proportional to the square root of the mass, for the same kinetic energy.
The horizontal distance traveled will be proportional to the launch velocity. So a halving of the mass will increase the velocity by a factor of ...
v2 = v1·√(1/(1/2)) = v1·√2
This means the second mass will land at a distance of about D√2, a value ...
greater than D but less than 2D.