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guajiro [1.7K]
3 years ago
11

Which of the following is used in Sonata II's prepared piano?

Physics
1 answer:
Delvig [45]3 years ago
8 0
It is C. Copper wire.
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The Heaviside function H is defined by H(t)={0 if t<0, 1 if t≥0 It is used in the study of electric circuits to represent the
Studentka2010 [4]

Answer:

V(t)= 240V* H(t-5)

Explanation:

The heaviside function is defined as:

H(t) =1 \quad t\geq 0\\H(t) =0 \quad t

so we see that the Heaviside function "switches on" whent=0, and remains switched on when t>0

If we want our heaviside function to switch on when t=5, we need the argument to the heaviside function to be 0 when t=5

Thus we define a function f:

f(t) = H(t-5)

The -5 term inside the heaviside function makes sure to displace the function 5 units to the right.

Now we just need to add a scale up factor of 240 V, because thats the voltage applied after the heaviside function switches on. (H(t-5) =1 when t\geq 5, so it becomes just a 1, which we can safely ignore.)

Therefore our final result is:

V(t)= 240V* H(t-5)

I have made a sketch for you, and added it as attachment.  

5 0
3 years ago
20 characters or more
andreev551 [17]

Answer:

yes 20 characters or more

Explanation:

3 0
2 years ago
What is electrical conductivity?
Luda [366]

Answer:

Electrical resistivity and its inverse, electrical conductivity, is a fundamental property of a material that quantifies how strongly it resists or conducts electric current. A low resistivity indicates a material that readily allows electric current. Resistivity is commonly represented by the Greek letter ρ.

5 0
3 years ago
Read 2 more answers
Now, using your mass (in kg), and the figures for g (in the table below), you can calculate your weight on other planets.
Licemer1 [7]

Answer:

1) Weight on Mercury

F =W=mg=68.11 \times 3.61 m.s^{-2}

Explanation:

do the same to the rest and use your calculator to find the weight in N.

3 0
3 years ago
Answer the amplitude part of the questions in 7, 8, & 9
erastova [34]
I actually believe for the first question, it would be complete destructive interference as the amplitude and the approximate wavelength for each are the same and will completely or entirely cancel out, rather than simply decreasing or lowering the amplitude as in the bottom question.

The amplitude for the first will be 0, as the 2 waves will cancel each other out. The amplitude of the second, will be 3x, I believe, assuming the amplitude of the first is 2x and the second is 1x, in a constructive interference, I believe the amplitudes would add up.

Likewise for the bottom, I believe you would be subtracting the supposed amplitude of the first which is 2x from 1x which would be 1x.
5 0
3 years ago
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