1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrews [41]
3 years ago
13

A small object of mass M is shot horizontally from a spring launcher that is attached to a table. All frictional forces are cons

idered to be negligible. The ball
strikes the ground a distance D from the base of the table, as shown in the figure. A second object of mass is launched from the same launcher such that
the spring is compressed the same distance as in the original scenario. The distance from the base of the table that the object lands is
А
greater than but less than D
B
D
greater than D but less than 2D
greater than or equal to 2D.

Physics
1 answer:
faltersainse [42]3 years ago
5 0

Answer:

  C.  greater than D, but less than 2D

Explanation:

The amount of potential energy in the system is a function of the compression of the spring. That is the same for both masses.

The potential energy is transferred to kinetic energy when the spring is released. The kinetic energy is jointly proportional to the mass and the square of the velocity. That is, the velocity is inversely proportional to the square root of the mass, for the same kinetic energy.

The horizontal distance traveled will be proportional to the launch velocity. So a halving of the mass will increase the velocity by a factor of ...

  v2 = v1·√(1/(1/2)) = v1·√2

This means the second mass will land at a distance of about D√2, a value ...

  greater than D but less than 2D.

You might be interested in
What represents the impulse of the force in a graph of force versus time?
vovikov84 [41]
In the graph of the force vs the time:
Force is the gradient of the momentum versus the time.

If we get the area under the curve in this graph:
it will be calculated as : force * time
which gives the change in momentum or the impulse.

Therefore, the area under the curve <span>represents the impulse of the force in a graph of force versus time</span>
7 0
4 years ago
high frequency sound waves have a shorter wavelength and a higher A. amplitude B. pitch C. wavelength? than low frequency sound
gizmo_the_mogwai [7]
Pitch of the sound increases as frequency increases. 
choose B pitch 
8 0
3 years ago
Read 2 more answers
If a force always acts perpendicular to an object's direction of motion, that force cannot change the object's kinetic energy.
laiz [17]
This is very good conceptual question and can clear your doubts regarding work-energy theorem.
Whenever force is perpendicular to the direction of the motion, work done by that force is zero.
According to work-energy theorem,
Work done by all the force = change in kinetic energy.

here, work done = 0.
Therefore, 
0=change in kinetic energy
This means kinetic energy remains constant.
Hope this helps
5 0
3 years ago
Hook's law describes an ideal spring. Many real springs are better described by the restoring force (FSp)s=−kΔs−q(Δs)^3, where q
kvasek [131]

Answer

given,

k = 250 N/m

q = 900 N/m³

(FSp)s=−kΔs−q(Δs)^3

work done = Force x displacement

W = \int {F. dx}

limits are x = 0 to x = 0.15 m

work done

W = \int_0^{0.15} (k x + q x^3)\ dx

W = [\dfrac{kx^2}{2}+\dfrac{qx^4}{4}+ C]_0^0.15

W = \dfrac{300\times 0.15^2}{2}+\dfrac{900\times 0.15^4}{4}

W = 3.375 + 0.1139

W = 3.3488 J

b) % cubic term =\dfrac{0.1139}{3.3488}

   % cubic term =3.4\ %

7 0
3 years ago
On a cold winter day when the temperature is −20∘C, what amount of heat is needed to warm to body temperature (37 ∘C) the 0.50 L
vlabodo [156]

Answer:

75.6J

Explanation:

Hi!

To solve this problem we must use the first law of thermodynamics that states that the heat required to heat the air is the difference between the energy levels of the air when it enters and when it leaves the body,

Given the above we have the following equation.

Q=(m)(h2)-(m)(h1)

where

m=mass=1.3×10−3kg.

h2= entalpy at 37C

h1= entalpy at -20C

Q=m(h2-h1)

remember that the enthalpy differences for the air can approximate the specific heat multiplied by the temperature difference

Q=mCp(T2-T1)

Cp= specific heat of air = 1020 J/kg⋅K

Q=(1.3×10−3)(1020)(37-(-20))=75.6J

4 0
3 years ago
Other questions:
  • A wave is moving at 40 cm/s. Its wave length is 8 cm. what is the frequency of the wave?
    13·1 answer
  • A car accelerates at 4 m/s2 for 5 seconds. the direction of its acceleration is due east (east = positive direction). if its ini
    7·1 answer
  • Coal and other fossil fuels are considered to be "nonrenewable" sources of energy. How does the use of nonrenewable fuels affect
    7·1 answer
  • The period of a 261-Hertz sound wave is
    6·1 answer
  • Kat driving 55 mph approaching a stop light. It takes her 15 seconds to completley atop at the stop light. what was her accelera
    9·1 answer
  • 9) Who was right about the atom, Bohr or Schrodinger?
    9·2 answers
  • What is the equator ?????e define​
    10·1 answer
  • A car accelerates from 0 to 72 km/ hour in 8 sec. what is the cars acceleration?
    12·1 answer
  • A spherical capacitor contains a charge of 3.50 nC when connected to a potential difference of 210.0 V. Its plates are separated
    11·1 answer
  • Why is the force of gravity less on the moon than on Earth
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!