Explanation:
Elastic collision is said to occur if the total kinetic energy is not conserved and if there is a rebound after collision
Step one
Analysis of the problem
Immediately after impact the car's velocity was zero making it a perfect elastic collision
Step two
Given
Mass of car M1=1800kg
Mass of truck M2=5200kg
Initial velocity of Car U1=44m/s
Initial velocity of truck U2=21m/s
Final velocity of car V1= 0m/s
Final velocity of truck V2=20m/s
Step three
According to the principle of conservation of momentum
Total momentum before collision
=M1U1+M2U2
Total momentum after impact
=M1V1+M2V2
M1U1+M2U2 =M1V1+M2V2
Substituting our data into the expression we have 1500*44+5800*21=1500*0+5800*20
=66000+1218000=11600
1284000=11600
From the solution the momentum before impact is 1284000Ns
Momentum after impact is 11600Ns
This is indicating that after impact there was loss in momentum as a result of the car having a velocity of zero
No, it is not possible.
A compound is a substance or material constituting of two or more elements that have been chemically combined together to form a new, different substance
Any elements that have been joined together chemically can only be separated back into their constituent elements by chemical means because the bonds holding them together can only be broken using chemical means.
A good example is sodium chloride, table salt. Poisonous chlorine gas and toxic sodium metal react together whereby sodium loses one electron which chlorine readily accepts and in the process an ionic bond is formed between the two resulting in a totally new, harmless compound , sodium chloride.
Only through electrolysis can sodium chloride be separated back into sodium and chlorine gas. No physical means can be used to do that.
Explanation:
I hope this helps, I got this from another person
Answer:
Time period of the osculation will be 2.1371 sec
Explanation:
We have given mass m = (B+25)
And the spring is stretched by (8.5 A )
Here A = 13 and B = 427
So mass m = 427+25 = 452 gram = 0.452 kg
Spring stretched x= 8.5×13 = 110.5 cm
As there is additional streching of spring by 3 cm
So new x = 110.5+3 = 113.5 = 1.135 m
Now we know that force is given by F = mg
And we also know that F = Kx
So 
Now we know that 
So 
