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Sliva [168]
3 years ago
15

The sweet taste of freshly picked corn (maize) is due to the high level of sugar in the kernels. Store-bought corn (several days

after picking) is not as sweet, because about 50% of the free sugar is converted to starch within one day of picking. To preserve the sweetness of fresh corn, the husked ears can be immersed in boiling water for a few minutes ("blanched") then cooled in cold water. Corn processed in this way and stored in a freezer maintains its sweetness. What is the biochemical basis for this procedure?
Chemistry
1 answer:
____ [38]3 years ago
3 0

Answer:

The main purpose of this method is the inactivation of enzymes in corn by denaturing them through the application of heat and then cold preservation to avoid the activity of remaining enzymes.

Explanation:

When freshly picked, sweet corn is high in sugar and low in starch.  As sweet corn sits after picking, the sugars in the kernel turn to starch.  This mutes the flavor and affects its texture when cooked.

This transformation in the nutrients in the corn is carried out by the enzymes present in the corn kernels.

Blanching is an important intermediate thermal processing step to enhance preservation and quality of foods by inactivating enzymes that can cause loss of flavor and color.

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Molecules in all organisms are composed in part of radioactive carbon-14. Which statement best explains the presence of carbon-1
lana66690 [7]

Answer:

The correct answer is option b, that is, the radioactive isotope reacts in the same way as stable isotopes in the chemical reactions in the body.

Explanation:

The carbon-14 atoms, which are created by the cosmic rays associates with oxygen to produce carbon dioxide that plants captivate naturally and comprise it into plant fibers by the process of photosynthesis. Afterward, the plants are consumed by animals and human beings, thus, they take in carbon-14 as well.  

The ratio of usual carbon-12 to carbon-14 in the air and in all the living species at a particular period is almost the same. These radioactive isotopes react in a similar manner as stable isotopes in the chemical reactions in the body.  

7 0
4 years ago
Are the phosphate groups on the interior or the exterior of the DNA molecule?
Makovka662 [10]

the double helix is hydrogen bonded through the bases only so the bases are inside the helix only

as adenine combines with thymine and guanine with cytosine

phosphate are in the exterior of it

sugar groups constitute the double helix.

3 0
3 years ago
HELPPPPPP!!!! SCIENCE!!!!!!
Nastasia [14]

Answer:

bn

Explanation:

3 0
3 years ago
Read 2 more answers
What causes the jet stream to move farther south?
Anni [7]
<span>Jet streams are the major means of transport for weather systems.  A jet stream is an area of strong winds ranging from 120-250 mph that can be thousands of miles long, a couple of hundred miles across and a few miles deep.  Jet streams usually sit at the boundary between the troposphere and the stratosphere at a level called the tropopause.  This means most jet streams are about 6-9 miles off the ground. Figure A is a cross section of a jet stream.
</span>

The dynamics of jet streams are actually quite complicated, so this is a very simplified version of what creates jets.  The basic idea that drives jet formation is this:  a strong horizontal temperature contrast, like the one between the North Pole and the equator, causes a dramatic increase in horizontal wind speed with height.  Therefore, a jet stream forms directly over the center of the strongest area of horizontal temperature difference, or the front.  As a general rule, a strong front has a jet stream directly above it that is parallel to it.  Figure B shows that jet streams are positioned just below the tropopause (the red lines) and above the fronts, in this case, the boundaries between two circulation cells carrying air of different temperatures.


7 0
3 years ago
If the gas inside the flask is cooled so that its pressure is reduced from 797.3 torr to a value of 715.7 torr what will be the
nadezda [96]
The differential pressure is
797.9 - 715.7 = 82.2 torr = 138815.25 Pa
The height of the mercury in the open-end arm is calculated using
ΔP = ρgh
The density of mercury is 13560 kg/m3
The height of the mercury is
138815.25 Pa = 13560 kg/m3 (9.81 m/s2) h
h = 1.04 m
4 0
3 years ago
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