All categories

3 years ago

If your weight is 120 pounds

Chemistry

1 answer:

denis23 [38]3 years ago

5 0

Explanation:

Weight is 120 pounds and mass is 54 kg

The mass of an object is same everywhere. If we were on the moon, its mass will remain to be 54 kg.

Weight of an object is given by :

$W=m\times g$

g is acceleration due to gravity on that surface

For moon, it is 1/6 the gravitational force on Earth, g = 1.63 m/s²

1 pound = 4.45 N

It means my weight is 533.78 N

On the surface of Moon is will be :

$W=\dfrac{533.78}{1.63}\\W=327.47\ N$

You might be interested in

1. 2Na + 2HCl --> 2NaCl + H2

snow_tiger [21]

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers

12.Chlorine has 18 electrons. It is a(n) cation anion atom

emmasim [6.3K]

Answer:

chlorine is therefore an anion

4 0

2 years ago

Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

notsponge [240]

Answer: The concentration of $Sn^{2+}$ in the cell is $9.0\times 10^{-3}M$

Explanation:

We are given:

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$ $E^o_{Zn^{2+}/Zn}=-0.76V$

Reduction half reaction: $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$ $E^o_{Sn^{2+}/Sn}=-0.136V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.136-(-0.76)=0.624V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}$

where,

$E_{cell}$ = electrode potential of the cell = 0.660 V

$E^o_{cell}$ = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=2.5\times 10^{-3}M$

$[Sn^{2+}]$ = ?

Putting values in above equation, we get:

$0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})$

$[Sn^{2+}]=9.0\times 10^{-3}M$

Hence, the concentration of $Sn^{2+}$ ions is $9.0\times 10^{-3}M$

3 0

3 years ago

How is the Law of Conservation of Mass, Matter, Phases of Matter, and Physical/Chemical Changes similar/connected to one another

kogti [31]

Answer:

Solids, liquids, and gases are made of tiny particles called atoms and molecules. In a solid, the particles are very attracted to each other. They are close together and vibrate in position but don't move past one another. In a liquid, the particles are attracted to each other but not as much as they are in a solid.

4 0

3 years ago

andrew-mc [135]

5 hope this helps I’m pretty sure it should be right

7 0

3 years ago