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3 years ago

9

Open-ended question: Differentiate between a solution and a two phase mixture. Brass is would be classified as which one of them

? Which would you classify a salad as?

1 answer:

Mariana [72]3 years ago

4 0

I would classify the salad as a mixture because you can separate the components<span />

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Two major discoveries of the gold foil experiment

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4 years ago

Consider the reaction: Mg(OH)₂ (s) ⇌ Mg²⁺ (aq) + 2 OH⁻ (aq)

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4 years ago

How many molecules are in 3.94g of SO2?

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To find the number of molecules, you need to first convert the mass into number of mol using the molar mass of SO2, simply add the atomic masses of each element and the number of times each element appears in the formula from the periodic table.

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4 years ago

An engineer is trying to create a fast reaction in a fuel mixture. Which should she do? A. Decrease the amount of fuel B. Lower

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4 years ago

Na2CO3 + 2HCl ---------> 2NaCl + CO2 + H2O How many moles of NaCl are produced from the reaction of 1.67 x 1022 molecules of

dexar [7]

Answer:

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

Explanation:

The balanced reaction is:

Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

Na₂CO₃: 1 mole
HCl: 2 moles
NaCl: 2 moles
CO₂: 1 mole
H₂O: 1 mole

On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

$amount of moles=\frac{1.67*10^{22}molecules*1mole }{6.023*10^{23}molecules}$

amount of moles= 0.0277 moles

In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

$amount of moles of NaCl=\frac{0.0277 moles of Na_{2} CO_{3}*2 moles of NaCl }{1 mole of Na_{2} CO_{3}}$

amount of moles of NaCl= 0.0554 moles

<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>

8 0

3 years ago