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Marrrta [24]
3 years ago
9

Find the difference. 7.6 - 5.88

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
7 0
The difference is -1.72
DerKrebs [107]3 years ago
4 0

Answer:

1.72

Step-by-step explanation:

Would end up being the difference.

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The height of a cuboid is 12cm,the volume is 1200cm3 find the side of the of a cuboid​
Tasya [4]

Answer:

area=volume/height

area=1200cm cubed/12cm

area=100cm squared

5 0
2 years ago
a college freshman must take a science course ,humanities course, and a mathematics course.if she ay select any of 6 science cou
12345 [234]
Answer: 96 ways

In this case, the freshman must take one class each from Science(6 courses), Humanities(4 courses) and Mathematics( 4 courses).
Then to know how many ways she can arrange you just need to multiply the each course count (it would different if she has to take more than one class).
The calculation would be: 6 x 4 x 4= 96 ways.
3 0
4 years ago
You have a net lease for $350 per month. You are responsible for the taxes, which are $6,000 per year. What is your monthly rent
pychu [463]

Answer: 850

Step-by-step explanation: 6,000 divided by 12 = 500 + 350 = 850

7 0
3 years ago
What is the modulus and argument after (StartRoot 3 EndRoot) (cosine (StartFraction pi Over 18 EndFraction) + I sine (StartFract
fgiga [73]

Answer:

|z| = 27 -- Modulus

\theta = \frac{\pi}{3} --- Argument

Step-by-step explanation:

Given

((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6

Required

Determine the modulus and the argument

We have that:

z = ((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6

Expand:

z = (\sqrt 3)^6(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6

z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6

A complex equation can be expressed as:

z = |z| e^{i\theta}

Where

|z| = modulus

\theta = argument

Where

e^{i\theta} = (cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})

So:

z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6 becomes

z = 27(e^{i\frac{\pi}{18}})^6

By comparison:

e^{i\theta} = (e^{i\frac{\pi}{18}})^6

This gives:

{i\theta} = i\frac{\pi}{18}}*6

{i\theta} = i\frac{6\pi}{18}}

{i\theta} = i\frac{\pi}{3}}

Divide through by i

\theta = \frac{\pi}{3}

Hence, the modulus, z is:

|z| = 27

And the argument \theta is

\theta = \frac{\pi}{3}

4 0
3 years ago
Simplify the expression 4p-5p-30p=
Fudgin [204]

Answer:

-31p

Step-by-step explanation:

........

6 0
3 years ago
Read 2 more answers
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