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4 years ago

Solve this inequality: 3p – 16 < 20.

Mathematics

1 answer:

BaLLatris [955]4 years ago

5 0

3 p - 16 < 20
3 p < 20 + 16
3 p < 36
Answer:
p < 12
or : p ∈ ( -∞ , 12 )

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"find the measure of each angle indicated"

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180-65=115°

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Solve this equation<br> y= -3x +3

kari74 [83]

Answer:

What do you want me to do? It is already solved

Step-by-step explanation:

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3 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

3 years ago

Answer n how to solve

Vladimir [108]

Answer:

The interior of the triangle are congruent as they are equal in size at point at point l, k, m proof is the line of symmetry shows a 4 way rotation.

We know from how the line represents 2 triangles that equally make an equal sided square should we draw lines

For the g, h, i, j to show a 4 way rotation- should we draw 2 more triangles.

The second shape has congruent angles as the rotation is 2 and angles shown indicate the symmetrical value as midway point are the same also. So while all 3 sets of the second angles are congruent if we make a square shape 8/8 angles have the same degree as one another as there will be 4 triangles in shape 1 and shape 2.

Whilst the rotation is less, this is simply as the base is on the outside and sides are the same- creating a wider perimeter as it enlarges the shape. this may confuse but to prove again we can compare a rotation to equal curve triangles folded within a regular circle shape or just like the first example create 4 triangles and draw 2 lines of symmetry. just like folding a regular square. For full flip rotation within a shape we have found side length is not equal but angles must be 3 of the same for 2 way rotation within a larger shape and 3 equal angles with longer length for rotation within its first found square shape.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers