Answer:
It's the PURPULE one
Step-by-step explanation:
BTW can u pls help me in my question thanks
Given: y = 2x^2 - 32x + 56
1) y = 2 [ x^2 - 16x] + 56
2) y = 2 [ (x - 8)^2 - 64 ] + 56
3) y = 2 (x - 8)^2 - 128 + 56
4) y = 2 (x - 8)^2 - 72 <----------- answer
Minimum = vertex = (h,k) = (8, - 72)
=> x-ccordinate of the minimum = 8 <-------- answer
Answer:
y=5/3x-3
Step-by-step explanation:
first, let's put 3x+5y=15 into y=mx+b form
move 3x to the other side
5y=-3x+15
divide by 5
y=-3/5x+3
now, perendicular lines have slopes that are negative and reciprocal.
With our new equation we can automatically find the slope, which would be 5/3.
now, we need to find b
plug the points (3,2) into y=5/3x+b
2=5/3(3)+b
2=5+b
-3=b
so that means that our equation will now be
y=5/3x-3.
Hope this helps!
