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sertanlavr [38]

2 years ago

13

The low temperature was 35 Degrees Fahrenheit. This was 13°F lower than the day time high temperature right in equation the dete

rminate which the high temperature was 48°F or 42°F.

1 answer:

Alex Ar [27]2 years ago

6 0

Answer:

48 hope this helped

Step-by-step explanation:

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The area of a triangle is found by multiplying half of the measure of its base by its height. The area of the following right tr

Scrat [10]

Answer:

AREA OF TRAINGLE =18

WE NO THE AREA OF 1/2 BH

B=6

PLUGGING IN THE VALUES

18 1/2 6 (H+1)

6=H+1

H=5

7 0

2 years ago

A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x overbar, is found

joja [24]

Answer:

(a) 80% confidence interval for the population mean is [109.24 , 116.76].

(b) 80% confidence interval for the population mean is [109.86 , 116.14].

(c) 98% confidence interval for the population mean is [105.56 , 120.44].

(d) No, we could not have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed.

Step-by-step explanation:

We are given that a simple random sample of size n is drawn from a population that is normally distributed.

The sample mean is found to be 113 and the sample standard deviation is found to be 10.

(a) The sample size given is n = 13.

Firstly, the pivotal quantity for 80% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 113

s = sample standard deviation = 10

n = sample size = 13

$\mu$ = population mean

<em>Here for constructing 80% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.</em>

<u>So, 80% confidence interval for the population mean, </u> $\mu$ <u> is ;</u>

P(-1.356 < $t_1_2$ < 1.356) = 0.80 {As the critical value of t at 12 degree

of freedom are -1.356 & 1.356 with P = 10%}

P(-1.356 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.356) = 0.80

P( $-1.356 \times }{\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.356 \times }{\frac{s}{\sqrt{n} } }$ ) = 0.80

P( $\bar X-1.356 \times }{\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.356 \times }{\frac{s}{\sqrt{n} } }$ ) = 0.80

<u>80% confidence interval for </u> $\mu$ = [ $\bar X-1.356 \times }{\frac{s}{\sqrt{n} } }$ , $\bar X+1.356 \times }{\frac{s}{\sqrt{n} } }$ ]

= [ $113-1.356 \times }{\frac{10}{\sqrt{13} } }$ , $113+1.356 \times }{\frac{10}{\sqrt{13} } }$ ]

= [109.24 , 116.76]

Therefore, 80% confidence interval for the population mean is [109.24 , 116.76].

(b) Now, the sample size has been changed to 18, i.e; n = 18.

So, the critical values of t at 17 degree of freedom would now be -1.333 & 1.333 with P = 10%.

<u>80% confidence interval for </u> $\mu$ = [ $\bar X-1.333 \times }{\frac{s}{\sqrt{n} } }$ , $\bar X+1.333 \times }{\frac{s}{\sqrt{n} } }$ ]

= [ $113-1.333 \times }{\frac{10}{\sqrt{18} } }$ , $113+1.333 \times }{\frac{10}{\sqrt{18} } }$ ]

= [109.86 , 116.14]

Therefore, 80% confidence interval for the population mean is [109.86 , 116.14].

(c) Now, we have to construct 98% confidence interval with sample size, n = 13.

So, the critical values of t at 12 degree of freedom would now be -2.681 & 2.681 with P = 1%.

<u>98% confidence interval for </u> $\mu$ = [ $\bar X-2.681 \times }{\frac{s}{\sqrt{n} } }$ , $\bar X+2.681 \times }{\frac{s}{\sqrt{n} } }$ ]

= [ $113-2.681 \times }{\frac{10}{\sqrt{13} } }$ , $113+2.681 \times }{\frac{10}{\sqrt{13} } }$ ]

= [105.56 , 120.44]

Therefore, 98% confidence interval for the population mean is [105.56 , 120.44].

(d) No, we could not have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed because t test statistics is used only when the data follows normal distribution.

6 0

2 years ago

Pls help answer <br> I’m thinking it’s negative but I’m not sure.

Digiron [165]

Negative i believe is the correct answer

3 0

2 years ago

Read 2 more answers

Which function in vertex form is equivalent to f(x) = x2 + 8 – 16x? f(x) = (x – 8)2 – 56 f(x) = (x – 4)2 + 0 f(x) = (x + 8)2 – 7

kkurt [141]

Answer:

f(x) = x² + 8 - 16x

= x² - 16x + 8

= (x² - 16x + 64) - 64 + 8

= (x + 8)² - 56

4 0

2 years ago

Read 2 more answers

The amount of stretch in a short bungee cord stretches 6 inches when stretched by a 3pound weight. A slinky stretches 3 feet whe

aleksklad [387]

Answer:

The slinky situation

Step-by-step explanation:

To make a rate, divide one value by the other.

For the short bungee,

6 inches ÷ 3 pound = 2 inches per pound

While the slinky,

36 inches (remember to convert feet to inches) ÷ 1 pound = 36 inches per pound

As you can tell by the numbers, 36 inches per pound is way better than the 2 inches per pound.

6 0

3 years ago