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3 years ago

It said it was wrong

Mathematics

1 answer:

IRINA_888 [86]3 years ago

5 0

Answer:

well then, what was right?

Step-by-step explanation:

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Enter the numerator and the denominator of the fraction in simplest form that is equal to 0.998¯¯¯¯¯¯¯¯.

Nookie1986 [14]

Answer:

998/1000

499/500 simplified

6 0

3 years ago

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Given f(x)=x^2+5 and g(x)=2x^3-1 find (f/g)(-3)

AlekseyPX

For this case we have the following functions:

$f (x) = x ^ 2 + 5\\g (x) = 2x ^ 3-1$

By definition of composition of functions we have:

$(f / g) (x) = \frac {f (x)} {g (x)}$

Then substituting:

$f (-3) = (- 3) ^ 2 + 5 = 9 + 5 = 14\\g (-3) = 2 (-3) ^ 3-1 = 2 (-27) -1 = -54-1 = -55$

So:

$(f / g) (- 3) = \frac {14} {- 55} = - 0.25$

Answer:

$(f / g) (- 3) = \frac {14} {- 55} = - 0.25$

7 0

3 years ago

Filipemarcosdesouza

Margaret [11]

Answer:

noted, thanks for the note

7 0

3 years ago

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If Diana walks forward and her angle looking to the top of the building changes to 40°, how much closer is she to the building?

elena55 [62]

The closer Diana gets to the building, the smaller the angle becomes

Diana is 17.6 feet closer to the building

<h3>How to calculate the distance from the building</h3>

To calculate the distance between her and the building, we make use of the following tangent ratio

$\tan(\theta) = \frac{h}{d}$

Where:

$\theta = 40^o$
h represents the height of the building; h = 130
d represents the distance from the building

So, we have:

$\tan(40) = \frac{130}{d}$

Make d the subject

$d = \frac{130}{\tan(40)}$

Evaluate tan(40)

$d = \frac{130}{0.8391}$

$d = 154.93$

Initially, Diana is at a distance of 172.53.

The difference in both distance is:

$\Delta d = 172.53 - 154.93$

$\Delta d = 17.6$

Hence, Diana is 17.6 feet closer to the building

Read more about trigonometry ratios at:

brainly.com/question/4326804

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2 years ago

Find the inverse of the given function. (pictured below)

zavuch27 [327]

Answer:

Step-by-step explanation:

f(x) = y = -1/2 × sqrt(x+3)

2y = -sqrt(x+3)

4y² = x + 3

x = 4y² - 3

now renaming this, so that the normal symbols and names are used for this function definition, so that the input variable is called "x" :

f-1(x) = 4x² - 3

basically, just by itself, this function would be defined for all possible real values of x.

but because it is the inverse of the original function, which generates only values of y<=0, then for the inverse function that same range applies for its input variable x

x<=0

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3 years ago