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Kipish [7]
3 years ago
5

Could 13.5 cm, 8.0 cm, and 3.5 cm be the side lengths of a triangle?

Mathematics
1 answer:
Sergio039 [100]3 years ago
6 0
The answer is no, it couldn't be because the side lengths do not adhere to the triangle inequality theorem. which states that the sum of the side lengths of any 2 sides of a triangle must exceed the length of the third side

3.5+8>13.5 Is not correct.

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After his alarm rings, Clarence has
Sonja [21]

Answer: 14 days

Step-by-step explanation:

Day 1: 1 minute snooze = 24 minutes

Day 2: 2 minute nooze = 23 minutes ; these examples show snooze time = days.

We can set up an equation for this situation: 25 - s = r ; where s = snooze time and r = time to get ready.

Given the problem, we can fill out this equation with: 25 - s = 11

When you solve this equation, time snoozed = 14.

We already know that snooze time = days, so days = 14.

I am not a professional, simply using prior knowledge!

Note- It would mean the world to me if you could mark me brainliest!

7 0
3 years ago
What is a multiplication equation that has a solution of 2/7
prisoha [69]
1/7 *2 =2/7 take denominator with 1 over it and multiply by numerator
4 0
3 years ago
Find the area of the shaded region. Round the the nearest tenth.
Brums [2.3K]

Answer:

226.084 sq.m.

Step-by-step explanation:

Radius of circle = 18.6 cm

Area of sector = \frac{\theta}{360^{\circ} }\pi r^2

Area of sector = \frac{123}{360} \times 3.14 \times (18.6)^2

Area of sector = 371.157 m^2

Area of triangle = \frac{1}{2} \times a \times b \times Sin x

a = OA = radius = 18.6 cm

b = OB = radius = 18.6 cm

x =123 °

Substitute the values in the formula

Area of triangle = \frac{1}{2} \times 18.6 \times 18.6 \times Sin 123

Area of triangle = 145.073 m^2

So, Area of shaded region = Area of sector - Area of triangle

                                            =371.157 m^2-145.073 m^2

                                            =226.084 m^2

Hence the area of the shaded region is 226.084 sq.m.

5 0
3 years ago
(WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST) Directed line segment is graphed below. Plot point R on the graph so that it spl
guajiro [1.7K]

Answer:

(0 , -1)

Step-by-step explanation:

WR = 4 + 2 = 6

WS = 1/3 x WR = 2   .... the point of 1:2 of WR

S (-2 + 2 , -4) i.e. (0,4)

The same reason: RQ = 1/3 x RY = 1/3 x (5 + 4) = 3

Q (-4 , -4 + 3) i.e. (-4, -1)

QP // RW

p (0 , -1)

4 0
3 years ago
F(x) = 2/x, g(x) = |x| -1 <br><br><br> What is the domain of (fog) (x)?<br><br> will mark brainliest
brilliants [131]

Answer:

x≠-1,1

Step-by-step explanation:

f(g(x)) is a composition where g(x) is is substituted for x in f(x).

Recall, f(x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.

|x|-1=0

|x|=1

x=1,-1

3 0
3 years ago
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