3 years ago

Could 13.5 cm, 8.0 cm, and 3.5 cm be the side lengths of a triangle?

1 answer:

6 0

The answer is no, it couldn't be because the side lengths do not adhere to the triangle inequality theorem. which states that the sum of the side lengths of any 2 sides of a triangle must exceed the length of the third side

3.5+8>13.5 Is not correct.

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it would be known as a mixed fraction....?

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3 years ago

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Can somebody please help me with work answer Pleaseee

liberstina [14]

Answer:

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Step-by-step explanation:

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2 years ago

Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position

Alenkinab [10]

Answer:

$\cos \theta=-\dfrac{8}{17}$

Step-by-step explanation:

Coordinates of Point b $=(-8,15)$

b lies on the circle whose equation is $x^2+y^2=289$

$x^2+y^2=17^2$

Comparing with the general form a circle with center at the origin: $x^2+y^2=r^2$

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

$\cos \theta=\dfrac{Adjacent}{Hypotenuse} \\$Adjacent=-8\\Hypotenuse=17\\\cos \theta=\dfrac{-8}{17} \\\cos \theta=-\dfrac{8}{17}$

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2 years ago

a $3 500.00 principal earns 3 interest compounded semiannually after 20 yeara what is the balance in the account

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3 years ago

Math Help Please....

stich3 [128]

Triangle ABE is similar to triangle CED (AAA)
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