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madreJ [45]
3 years ago
11

Help please. Find A if possible

Mathematics
2 answers:
zlopas [31]3 years ago
4 0

Answer:

10

Step-by-step explanation

Dimas [21]3 years ago
4 0
10 big dog he right take it easy
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X(x^3+4x^2-65x+132)=0
Nonamiya [84]

Answer:

0,3,4,-11

Step-by-step explanation:

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3 years ago
Solve for x I need help on this question
AlexFokin [52]

Answer:

x\approx7.8

Step-by-step explanation:

In relation to the given angle, we are given the triangle's opposite side and hypotenuse. Therefore, we use the sine function to set up a proportion and solve for the opposite side:

sin(\theta)=\frac{opposite}{hypotenuse}

sin(23^\circ)=\frac{x}{20}

20sin(23^\circ)=x

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3 0
2 years ago
Help help help help help help
Misha Larkins [42]

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<h2>189 MILES</h2>

3 0
3 years ago
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
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