3 over 1 + 6 over 60
[3 over 1 × 60 over 60] + 6 over 60
180 over 60 + 6 over 60 ➡ 186 over 60
186 over 60 ➡ 31 over 10
Then we divide 31 from 10 which give you the quotient of 3.1..
(((Meaning ➡ '"3.1" would be your answer)))
The solution is B = 43
Step-by-step explanation:
Simplify and solve for the unknown for 5(B + 3) = 4(B - 7) + 2B
- Simplify each side
- Add the like terms in each side if need
- Separate the unknown in one side and the numerical term in the other side to find the value of the unknown
∵ 5(B + 3) = 4(B - 7) + 2B
- Multiply the bracket (B + 3) by 5 in the left hand side and multiply
the bracket (B - 7) by 4 in the right hand side
∵ 5(B + 3 ) = 5(B) + 5(3) = 5B + 15
∵ 4(B - 7) = 4(B) - 4(7) = 4B - 28
∴ 5B + 15 = 4B - 28 + 2B
- Add the like terms in the right hand side
∵ 4B + 2B = 6B
∴ 5B + 15 = 6B - 28
- Add 28 to both sides
∴ 5B + 43 = 6B
- Subtract 5B from both sides
∴ 43 = B
- Switch the two sides
∴ B = 43
To check the answer substitute the value of B in each side if the two sides are equal then the solution is right
The left hand side
∵ 5(43 + 3) = 5(46) = 230
The right hand side
∵ 4(43 - 7) + 2(43) = 4(36) + 86 = 144 + 86 = 230
∴ L.H.S = R.H.S
∴ The solution B = 43 is right
The solution is B = 43
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Answer:
Yes . Divide by 10 for 10/20 to get 1/2.
10/10= 1
20/10= 2
10/20= 1/2
Answer:
The correct option is D.
i.e.
is the correct option.
The correct graph is shown in attached figure.
Step-by-step explanation:
Considering the function
![\mathrm{Range\:of\:}\frac{1}{x\left(x+4\right)}:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:-\frac{1}{4}\quad \mathrm{or}\quad \:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{1}{4}]\cup \left(0,\:\infty \:\right)\end{bmatrix}](https://tex.z-dn.net/?f=%5Cmathrm%7BRange%5C%3Aof%5C%3A%7D%5Cfrac%7B1%7D%7Bx%5Cleft%28x%2B4%5Cright%29%7D%3A%5Cquad%20%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Af%5Cleft%28x%5Cright%29%5Cle%20%5C%3A-%5Cfrac%7B1%7D%7B4%7D%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Af%5Cleft%28x%5Cright%29%3E0%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A-%5Cfrac%7B1%7D%7B4%7D%5D%5Ccup%20%5Cleft%280%2C%5C%3A%5Cinfty%20%5C%3A%5Cright%29%5Cend%7Bbmatrix%7D)
So, the correct graph is shown in attached figure.
Therefore, the correct option is D.
i.e.
is the correct option.
