Answer:
Midpoint is 
Step-by-step explanation:
Midpoint = 
= 
= 
= 
Midpoint is (-37/2, 14)
Answer:
-81
Step-by-step explanation:
-6(2x² + 5x) - 9
substitute -4 for 'x'
-6[2(-4)² + 5(-4)] - 9
-6[2(16) + (-20) - 9]
-6(32 - 20) - 9
-6(12) - 9
-72 - 9 = -81
Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer:
hahahahahahaa that's truly
Answer:
-1562500
Step-by-step explanation:
15625 × (-2) + (-15625) × 98 = -31250 + (-1531250)
= -31250 - 1531250
= -1562500