Answer: 7.88375g
Explanation:
Here is the dimensional analysis table
7g O2 | 1 mol O2 | 2 mol H2O | 18.02 g H2O
| 32 g O2 | 1 mol O2 | 1 mol H2O
You use grams to convert to moles of O2, then use that to find grams of H20
Answer: E=∆H*n= -40.6kj
Explanation:
V(CO) =15L=0.015M³
P=11200Pa
T=85C=358.15K
PV=nRT
n=(112000×0.015)/(8.314×358.15)
n(Co)= 0.564mol
V(Co)= 18.5L = 0.0185m³
P=744torr=98191.84Pa
T= 75C = 388.15k
PV=nRT
n= (99191.84×0.0185)/(8.314×348.15)
n(H2) = 0.634mol
n(CH30H) =1/2n(H2)=1/2×0.634mol
=0.317mol
∆H =∆Hf{CH3OH}-∆Hf(Co)
∆H=-238.6-(-110.5)
∆H = 128.1kj
E=∆H×n=-40.6kj.
Answer : The number of moles of water will be, 1.235 moles
Solution : Given,
Mass of 
= 42 grams
Molar mass of = 34 g/mole
First we have to calculate the moles of
Now we have to calculate the moles of water.
The balanced chemical reaction will be,
From the balanced reaction, we conclude that
As, 2 moles of decomposes to give 2 moles of water
So, 1.235 moles of decomposes to give 1.235 moles of water
Therefore, the number of moles of water will be, 1.235 moles
The atomic mass is the sum of the protons and neutrons in an atom
Answer:
c = 0.528 J/g.°C
Explanation:
Given data:
Mass of titanium = 43.56 g
Heat absorbed = 0.476 KJ = 476 j
Initial temperature = 20.5°C
Final temperature = 41.2°C
Specific heat capacity = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 41.2°C - 20.5°C
ΔT = 20.7 °C
476 J = 43.56 g × c × 20.7 °C
476 J = 901.692 g.°C × c
c = 476 J / 901.692 g.°C
c = 0.528 J/g.°C
