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kompoz [17]
2 years ago
13

Ion-dipole interactions can occur between any ion and any molecule with a dipole. Identify all of the following pairs of species

that can interact via ion-dipole forces. chegg
Chemistry
1 answer:
Zigmanuir [339]2 years ago
4 0

An ion-dipole interaction is the result of an electrostatic interaction between a charged ion and a molecule that has a dipole. It is an attractive force that is commonly found in solutions, especially ionic compounds dissolved in polar liquids. A cation can attract the partially negative end of a neutral polar molecule, while an anion attracts the positive end of a polar molecule. Ion-dipole attractions become stronger as the charge on the ion increases or as the magnitude of the dipole of the polar molecule increases.

This force of attraction is between an ion and a charge , it is weaker force than covalent bond and ionic bond . EX - The ion dipole interaction takes place between water and sodium ion , in it there is a small charge on oxygen molecule in water which is attracted by sodium charge .

Most commonly found in solutions. Especially important for solutions of ionic compounds in polar liquids.

A positive ion (cation) attracts the partially negative end of a neutral polar molecule.

to learn more about dipole interactions:-

https://brainly.in/question/1157107

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Answer:

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3 years ago
Which of the following contains properties of magnesium, Mg?
tekilochka [14]

Answer:

Option B. Malleable, Conductor, High melting point, Lustrous

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6 0
3 years ago
What is the half-life of A? What will the pressure, initially 32.1 kPa, at
kodGreya [7K]

Answer:

a) 32.09 kPa

b) 32.09 kPa

Explanation:

Given data:

rate constant = 3.56\times 10^{-7} s^{-1}

initial pressure is = 32.1 kPa

half life of A is calculated as

t_{1/2} = \frac{ln 2}{k}

t_{1/2} = \frac{ln 2}{3.56\time 10^{-7}}

t_{1/2} = = 1.956 \times 10^6 s

for calculating pressure we have follwing expression

ln p = ln P_o - kt

P =P_o e^{-kt}

a) P = 32.1 e^{-3.56\times 10^{-7} \times 10} = 32.09 kPa

b) P = 32.1 e^{-3.56\times 10^{-7} \times 10\times 60} = 32.09 kPa

5 0
3 years ago
A 39 foot ladder is resting against a wall that is 36 feet high. What is
alina1380 [7]

So if you take a 39 ft ladder and place its base 15 feet from the base of the wall, when you lean the ladder against the wall, the point where the ladder rests against the wall will be 36 feet above the ground.

Answer: 15 feet
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Hope this helps you understand this problem a little better.
6 0
3 years ago
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Answer:

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Explanation:

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5 0
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