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From: Yy Ss Hh 8 different gametes can be formed
- 5 Eye Color Genes = 243 genotypes
- 10 Eye Color Genes= 59049 genotypes
- 20 Eye Color Genes= 3,486,784,401 genotypes
This is further explained below.
<h3>What is a gamete?</h3>
Generally, Gametes are the cells of an organism that are responsible for reproduction. In certain contexts, they are also referred to as egg cells and sperm cells.
The popular word for female gametes is ova, whereas the common name for male gametes is sperm. Ovum and egg cells are other frequent names for female gametes.
Gametes are instances of haploid cells since they only contain a single copy of each chromosome. Haploid cells are described as having only one copy of each chromosome.
In conclusion, For 5 Eye Color Genes
3^n is implored hence
3^5=243 genotypes
Repeating said pattern e have
- 10 Eye Color Genes= 59049 genotypes
- 20 Eye Color Genes= 3,486,784,401 genotypes
Read more about gamete
brainly.com/question/2569962
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CQ
4. Consider the following genotype: Yy Ss Hh. We have now added the gene for height: Tall (H) or Short (h).
a. How many different gamete combinations can be produced?
b. Many traits (phenotypes), like eye color, are controlled by multiple genes. If eye color were controlled by the number of genes indicated below, how many possible genotype combinations would there be in the following scenarios?
a. 5 Eye Color Genes:
b. 10 Eye Color Genes:
c. 20 Eye Color Genes:
<h3>Answer:</h3>
Excess Reagent = NBr₃
<h3>Solution:</h3>
The Balance Chemical Equation for the reaction of NBr₃ and NaOH is as follow,
2 NBr₃ + 3 NaOH → N₂ + 3 NaBr + 3 HBrO
Calculating the Limiting Reagent,
According to Balance equation,
2 moles NBr₃ reacts with = 3 moles of NaOH
So,
40 moles of NBr₃ will react with = X moles of NaOH
Solving for X,
X = (40 mol × 3 mol) ÷ 2 mol
X = 60 mol of NaOH
It means 40 moles of NBr₃ requires 60 moles of NaOH, while we are provided with 48 moles of NaOH which is Limited. Therefore, NaOH is the limiting reagent and will control the yield of products. And NBr₃ is in excess as some of it is left due to complete consumption of NaOH.
Answer:
Option B. 4 moles of the gaseous product
Explanation:
Data obtained from the question include:
Initial volume (V1) = V
Initial number of mole (n1) = 2 moles
Final volume (V2) = 2V
Final number of mole (n2) =..?
Applying the Avogadro's law equation, we can obtain the number of mole of the gaseous product as follow:
V1/n1 = V2/n2
V/2 = 2V/n2
Cross multiply
V x n2 = 2 x 2V
Divide both side by V
n2 = (2 x 2V)/V
n2 = 2 x 2
n2 = 4 moles
Therefore, 4 moles of the gaseous product were produced.