Answer:
2.86L
Explanation:
Given parameters:
V1 = 2.1L
T1 = 200°C = 200 + 273 = 473K
T 2 = 370°C = 370 + 273 = 643K
Unknown:
V2 = ?
Solution:
Since pressure is constant, we apply the Charles's law;
=
V is volume
T is the temperature
1 is the initial state
2 is the new state
=
V2 = 2.86L
I am not 100% sure but it should be butyl-cyclohexane
<span>A pure substance contains only one kind of molecule, and a mixture is a combination of two or more pure substances.</span>
The given question is incomplete. The complete question is :
The thermal decomposition of phosphine (PH3) into phosphorus and molecular hydrogen is a first-order reaction:
The half-life of the reaction is 35.0 s at 680°C. Calculate the first order rate constant.
Answer: a) The first order rate constant is ![0.0198s^{-1}](https://tex.z-dn.net/?f=0.0198s%5E%7B-1%7D)
b) The time after which 95% reactions gets completed is 151 seconds
Explanation:
Expression for rate law for first order kinetics is given by:
![t=\frac{2.303}{k}\log\frac{a}{a-x}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7Ba%7D%7Ba-x%7D)
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) for finding the rate constant
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
![t_{\frac{1}{2}}=\frac{0.693}{k}](https://tex.z-dn.net/?f=t_%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cfrac%7B0.693%7D%7Bk%7D)
![k=\frac{0.693}{35.0s}=0.0198s^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B0.693%7D%7B35.0s%7D%3D0.0198s%5E%7B-1%7D)
The first order rate constant is ![0.0198s^{-1}](https://tex.z-dn.net/?f=0.0198s%5E%7B-1%7D)
b) for completion of 95 % of reaction
![t=\frac{2.303}{k}\log\frac{100}{100-95}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7B100%7D%7B100-95%7D)
![t=\frac{2.303}{0.0198}\log\frac{100}{5}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7B0.0198%7D%5Clog%5Cfrac%7B100%7D%7B5%7D)
![t=151 s](https://tex.z-dn.net/?f=t%3D151%20s)
The time after which 95% reactions gets completed is 151 seconds
The number of valence electrons in sulfur is 6. In its highest energy occupied electron shell, it has 6 electrons (3s2 and 3p4, summing to 6 electrons, to be exact).