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Alex_Xolod [135]
3 years ago
10

HELP ME WITH THIS AND ILL GIVE YOU BRAINLIST !!!! <3 plss

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0
11. 9 + 8 = 8 + 9
12. 91 + 0 = 91
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Find the distance between the points.<br> (r, s) and (0, 0)
zhenek [66]

Answer:  \sqrt{r^2+s^2

=====================================================

Reason:

Plot the points (0,0) and (r,s). You can place (r,s) anywhere you want.

Connect the two points mentioned and form a right triangle such that the segment from (0,0) to (r,s) is the hypotenuse of said right triangle.

The horizontal leg has a length of r-0 = r units, while the vertical leg will be 's' units.

Check out the diagram below.

We then apply the pythagorean theorem to say r^2+s^2 = h^2 where h is the hypotenuse. Solving for h gets us h = \sqrt{r^2+s^2}. We only focus on the positive square root since a negative hypotenuse makes no sense.

Since we made the hypotenuse the segment with endpoints (r,s) and (0,0), this means the hypotenuse length and the distance are the same thing.

Therefore, the distance from (r,s) to (0,0) is \sqrt{r^2+s^2}

As an alternative, you can use the distance formula to get the same answer. The distance formula is effectively the pythagorean theorem phrased a different way.

5 0
2 years ago
1. A dilation with a scale factor of 4 and centered at the origin is applied to AB¯¯¯¯¯ with endpoints A(1, 3) and B(5, 3). Drag
mafiozo [28]
1. (-4,-1) 2.A' (4,12) B'(20,12) 3.B' 4.2  5. 1/8 hope u got them all right  :p 
4 0
3 years ago
Read 2 more answers
Find all solutions of the equation in the interval [0, 2pi).
natali 33 [55]

Answer:

Step-by-step explanation:

Begin by squaring both sides to get rid of the radical. Doing that gives you:

sin^2x=1-cosx

Now use the Pythagorean identity that says

sin^2x =1-cos^2x and make the replacement:

1-cos^2x=1-cosx. Now move everything over to one side of the equals sign and set it equal to 0 so you can factor:

1-cos^2x+cosx-1=0 and then simplify to

cosx-cos^2x=0

Factor out the common cos(x) to get

cosx(1-cosx)=0 and there you have your 2 trig equations:

cos(x) = 0 and 1 - cos(x) = 0

The first one is easy enough to solve. Look on the unit circle and see where, one time around, where the cos of an angle is equal to 0. That occurs at

x=\frac{\pi }{2},\frac{3\pi}{2}

The second equation simplifies to

cos(x) = 1

Again, look to the unit circle and find where the cos of an angle is equal to 1. That occurs at π only.

So, in the end, your 3 solutions are

x=\frac{\pi}{2},\pi,\frac{3\pi}{2}

8 0
3 years ago
Median is 28; 16, 24, x, 48
Pachacha [2.7K]
X=32 because when you have an even set of numbers, you have to take the two in the middle and find the mean of them:
24+x=28•2
24+x=56
x=32
5 0
3 years ago
The quotient of five times a number and 7 is no more than 10
Akimi4 [234]
The sentence in numerical form is 5x/7≤10
to solve, multiply by 7
5x≤70
lastly, divide by 5
x≤14
3 0
3 years ago
Read 2 more answers
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