The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
Answer:
5:9
Step-by-step explanation:
It's just a way to set up ratios. Whichever number is said first gets put down first, then the number after gets put after.
So, 5:9
Or, you could write it as 5 footballs to 9 baseballs.
This is just my simple understanding of what you're asking since you asked what the ratio is.
Hope I helped!
Answer:
Step-by-step explanation:
-1/4x>8
x>8/(-1/4)
x>(8/1)(-4/1)
x>-32/1
x>-32
x<-32
The answer is D.
--------------------------
-3t+7>=9
-3t>=9-7
-3t>=2
t>=2/-3
t>=-2/3
t<=-2/3
The answer is A.
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