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mel-nik [20]
3 years ago
12

On Saturday morning, Owen earned $27. By the end of the afternoon he had earned a total of $62. Enter an equation, using x as yo

ur variable, to determine whether Owen earned $35 or $33 on Saturday afternoon.
Mathematics
2 answers:
Leviafan [203]3 years ago
6 0
Y
=
−
2
x
+
5
y
=
-
2
x
+
5
Use the slope-intercept form to find the slope and y-intercept.
Tap for more steps...
Slope:
−
2
-
2
y-intercept:
(
0
,
5
)
(
0
,
5
)
Any line can be graphed using two points. Select two
x
x
values, and plug them into the equation to find the corresponding
y
y
values.
Tap for more steps...
x
y
0
5
5
2
0
HACTEHA [7]3 years ago
4 0

Answer:just hart me n I will help

Step-by-step explanation:

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Z is..? The problem is attached as a png!
VikaD [51]

Answer:

Step-by-step explanation:

What i would do is multiply both sides by 2z + 1

so you get z-6=20z+10

-19z=16

z=-16/19

5 0
2 years ago
Read 2 more answers
a customer buys $12.42 in merchandise and gives the cashier a ten dollar bill, a five dollar bill, a dime, a nickel and two penn
Dmitry [639]
Her correct change would be $2.75 cents, to get this answer, just subtract 12.42 from 15.17
Hope this helped you!! ( :
4 0
3 years ago
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Factor the expression completely 7v5w + 7vw5 + 7u4vw
makvit [3.9K]
7v^5w=7vw\cdot v^4\\7vw^5=7vw\cdot w^4\\7u^4vw=7vw\cdot u^4\\\\7u^5w+7vw^5+7u^4vw=7vw(v^4+w^4+u^4)
8 0
3 years ago
Suppose a large shipment of laser printers contained 22% defectives. If a sample of size 276 is selected, what is the probabilit
Mrrafil [7]

Answer:

The probability that the sample proportion will differ from the population proportion by less than 6% is 0.992.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\mu_{\hat p}=p\\\\

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The information provided is:

p=0.22\\n=276

As the sample size is large, i.e. <em>n</em> = 276 > 30, the Central limit theorem can be used to approximate the sampling distribution of sample proportion.

Compute the value of P(\hat p-p as follows:

P(\hat p-p

Thus, the probability that the sample proportion will differ from the population proportion by less than 6% is 0.992.

6 0
3 years ago
If it takes 5/6 yards of fabric to make a dress, then how many yards will it take to make 8 dresses?​
saul85 [17]

Answer:

Improper Fraction: 20/3 yards

Mixed number: 6 2/3

Step-by-step explanation:

If 1 dress needed 5/6 yards to complete

then 8 dress needed

8 x 5/6 yards

which is 20/3 yards

I hope this helps

8 0
3 years ago
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