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marysya [2.9K]
3 years ago
13

Students in a large statistics class were randomly divided into two groups. The first group took the midterm exam with soft musi

c playing in the background, and the second group took the exam with no music playing. After the exam was completed, a researcher compared deidentified exam scores of the two groups.
Which of the following is the reason this experiment was not blind?

A. The sample sizes in both groups was large.
B. The students knew whether or not music was playing while they were taking the exam.
C. Students were randomized into the two groups.
D. Some of the students may not have studied for the exam.
E. Researchers looked at exam scores for the two groups.
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0

Answer:

The correct option is (B).

Step-by-step explanation:

In case of a blind experiment the participants are divided into groups: one is the treatment group and the other is a control group.

The treatment group are provided with the treatment whereas the control group is not provided with the treatment instead they are given placebos.

To keep the experiment bias free the participants are not informed of the group they belong.

In this case an experiment is conducted to determine the effect of music on studying.

One groups studies with music whereas the other studies without music.

But here the students know which group they belong as they can hear the music playing in the background. This effects the results of the experiment.

Thus, the experiment is not blind.

The correct option is (B).

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Step-by-step explanation:

This is a biased sample because only students with strong opinions are likely going to volunteer or show interest in representing the school at the board meeting. This sample is a voluntary type sample, and at such the conclusion is not valid. This sample is biased because a group or population of students have a higher or lower sampling probability.

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If n+h/5=f+9/9, then n/5=
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------------------------------------------------------------------
Question
------------------------------------------------------------------
\boxed { \frac{n+h}{5}  =  \frac{f+9}{9}}

------------------------------------------------------------------
Split the fraction on the left
------------------------------------------------------------------
\boxed { \frac{n}{5} + \frac{h}{5}  = \frac{f + 9}{9}}

------------------------------------------------------------------
Take away h/5 from both sides
------------------------------------------------------------------
\boxed { \frac{n}{5}  = \frac{f+9}{9} - \frac{h}{5}}

------------------------------------------------------------------
Change the denominator to be the same
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\boxed { \frac{n}{5} = \frac{5f+45}{45} - \frac{9h}{45}}

------------------------------------------------------------------
Put it into single fraction
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\boxed { \frac{n}{5} = \frac{5f+45-9h}{45} }

-------------------------------------------------------------------
Rearrange (This step may not be necessary)
------------------------------------------------------------------
\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }


\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}

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