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4 years ago

Which scenario is an example of a physical change?

Physics

2 answers:

klasskru [66]4 years ago

5 0

Answer:

Lead is melted into a liquid to form pellets.

schepotkina [342]4 years ago

4 0

Answer:

Explanation:

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It's D) valid and testable.

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4 years ago

What is the acceleration of a car that maintains a constant velocity of 100km/h for 10 s

Mademuasel [1]

A constant velocity means the acceleration is zero.

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3 years ago

Read 2 more answers

What affects sounds at their source

zheka24 [161]

Answer:

that's called Doppler effect

Explanation:

its observed because the distance between the source of sound and the observer is changing. If the source and the observer are approaching, then the distance is decreasing and if the source and the observer are receding.

-Hops

4 0

4 years ago

Steam is leaving a 4-L pressure cooker whose operating pressure is 150 kPa. It is observed that the amount of liquid in the cook

Anna71 [15]

Answer:

The mass flow rate is 2.37*10^-4kg/s

The exit velocity is 34.3m/s

The total flow of energy is 0.583 KJ/KgThe rate at which energy leave the cooker is 0.638KW

7 0

2 years ago

A 397-N wheel comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it is rotating at 25.

AleksAgata [21]

Answer:

h = 14.4 m

Explanation:

The height can be calculated by energy conservation:

$K_{r} + K_{t} - W = E_{p}$

Where:

W: is the work

$E_{p}$ : is the potential energy

$K_{r}$ : is the rotational kinetic energy

$K_{t}$ : is the transitional kinetic energy

Initially, the wheel has rotational kinetic energy and translational kinetic energy, and then when stops it has potential energy.

$K_{r} + K_{t} - W = E_{p}$

$\frac{1}{2}I\omega_{0}^{2} + \frac{1}{2}mv^{2} - W = mgh$

Where:

I: is the moment of inertia = 0.800 mr²

ω₀: is the angular speed = 25.0 rad/s

m: is the mass = P/g = 397 N/9.81 m*s⁻² = 40.5 kg

v: is the tangential speed = ω₀r²

Now, by solving the above equation for h we have:

$h = \frac{\frac{1}{2}(I\omega_{0}^{2} + mv^{2}) - W}{mg}$

$h = \frac{\frac{1}{2}(I\omega_{0}^{2} + m(\omega_{0}*r)^{2}) - W}{mg}$

$h = \frac{\frac{1}{2}(0.800*40.5 kg*(0.600 m)^{2}*(25.0 rad/s)^{2} + 40.5 kg*(25.0 rad/s*0.600 m)^{2}) - 2500 J}{40.5 kg*9.81 m/s^{2}} = 14.4 m$

Therefore, the height is 14.4 m.

I hope it helps you!

4 0

3 years ago