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aksik [14]
3 years ago
13

Which is the better deal?

Mathematics
2 answers:
g100num [7]3 years ago
5 0
It cant be 5. so that narrows down 1 2 and 3. 

isnt it obvious? it would be 3.
solniwko [45]3 years ago
4 0
3 dozen cookies for 3.60 dollars
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Genevieve loves 30% off wing night. She orders 12 wings that normally cost 1.25$ each. If the sales tax rate is 6.75%, how much
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Solve for r.<br> - 8x + 14 &gt; 60 OR<br> - 4r + 50 &lt; 58<br> Choose 1 answer:
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R would equal 2 i think
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Use elimination method to solve the silmutaneous equations<br> 2x +3y=1<br> 3x=2y+8<br> (4marks)
kotegsom [21]

Answer:

2x +3y=1⇒equation 1

3x=2y+8

3x-2y=8⇒equation 2

by elimination method,

2x+3y=1 ×2

3x-2y=8 ×3

4x+6y=2

9x-6y=24

cut 6y and -6y

4x+6y=2

9x-6y=24

---------------

13x+0=26

13x=26

x=26/13

x=2

substitute x=2 in equation 1

2(2)+3y=1

4+3y=1

3y=1-4

3y=-3

y=-3/3

y=-1

therefore, x=2 and y=-1

hope it helps u!

6 0
3 years ago
Carly left for school at 8:15.she left school at 2:45.if she arrived at 8:45,how many hours was she in the school
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3 0
2 years ago
at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t
baherus [9]

The probability that a student participates in both sports and drama is 0.14.

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If A and B are any two events, then the probability of the joint event (A\cup B) is given by the following formula: P(A\cup B)=P(A)+P(B)-P(A\cap B)

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose S denotes that "a student participates in sports" and D denotes that "a student participates in drama".
So, we have P(S)=\frac{42}{100}=0.42, P(D)=\frac{25}{100}=0.25, P(S\cup D)=\frac{53}{100}=0.53.

We want to find the probability that a student participates in both sports and drama i.e., we want to find P(S\cap D).

By the above formula, we obtain:

P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}

Therefore, the probability that a student participates in both sports and drama is 0.14.

To learn more about probability, refer: brainly.com/question/24756209

#SPJ9

6 0
1 year ago
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