The values of a, b, and c in given quadratic equation are:
a = 6 and b = -9 and c = 7
<em><u>Solution:</u></em>
Given quadratic equation is:

Let us first convert the given quadratic equation to standard form
The standard form is
with a, b, and c being constants, or numerical coefficients, and x is an unknown variable

Now we have to find the values of a, b, c

Thus comparing
with standard form of quadratic equation 
a = 6
b = -9
c = 7
Thus values of a, b, and c are found