Answer:
6.05 m/s
Explanation:
In order for the puck to reach the top of the ramp, its initial kinetic energy must be equal to its final potential energy.
So we can write:
(1)
where
m = 100 g = 0.1 kg is the mass of the puck
v is the initial speed of the puck
is the acceleration due to gravity
h is the height of the ramp
Here we know that
d = 4.60 m is the length of the ramp
is the angle of the ramp
So its height is
So now we can re-arrange eq (1) to find the minimum speed of the puck:
Answer:
- <u>Star, Triangle, Circle, Rhombus, Square</u>.
- <u>Left, Down, Right, Down, Up</u>.
- <u>2,3,2,4</u>.
- <u>L,O,O,K,I,N,G,F,L,Y</u>.
Explanation: You're welcome ✓
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Answer: 0.8 m
Explanation:
Velocity of throw = 4m/s
Maximum Height attained(h) =?
Downward acceleration experienced = 10m/s^2
Using the relation:
v^2 = u^2 + 2aS
v = final Velocity = 0 (at maximum height)
u = Initial Velocity = 4
a = g downward acceleration = - 10
0 = 4^2 + 2(-10)(S)
0 = 16 - 20S
20S = 16
S = 16 / 20
S = 0.8m
Maximum Height attained = 0.8m
