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BARSIC [14]
4 years ago
7

In a lab, the mass of object A is 2.5 kg. Object A weighs:

Physics
2 answers:
Zinaida [17]4 years ago
8 0

Answer:

The weight of the object is 24.5 Newton.

Explanation:

It is given that,

The mass of an object, m = 2.5 kg

We need to find its weight. We know that the weight of an object can be calculated by the product of mass and acceleration.

W = m g

g is acceleration due to gravity.

W=m\times g

W=2.5\ kg\times 9.8\ m/s^2

W = 24.5 Newton

So, the mass of the object is 24.5 Newton. Hence, this is the required solution.

kondor19780726 [428]4 years ago
5 0
Weight of object = mass x acceleration due to gravity
                             =  2.5 x 9.8
                             =   24.5N

Hence option B is correct.
Hope this helps!!
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20 cubic inches of a gas with an absolute pressure of 5 psi is compressed until its pressure reaches 10 psi. What's the new volu
boyakko [2]

It is given that that initial volume of gas is 20 cubic inches.

The initial pressure is given as 5 psi.

The final pressure is given as 10 psi

We are asked to calculate the final volume.

Let initial and final volume of gas is denoted as v_{1} \ and\ v_{2}

Let the initial and final pressure of gas is denoted as p_{1} \ and\ p_{2}

As per the question the temperature of a gas is constant.

From Boyle's law we know that pressure of a given mass of a gas is inversely proportional to the applied volume at constant temperature.

Hence mathematically

                                p\ \alpha\ \frac{1}{v}

                                pv=constant

                                p_{1} v_{1} =p_{2} v_{2}

                                v_{2} =\frac{p_{1}v_{1} }{p_{2} }

Putting the values of these respective quantities as mentioned above we get-

                                  v_{2} =\frac{5\ psi*20 cubic\ inches}{10\ psi}

                                         =10\ cubic\ inches        [ans]    


8 0
3 years ago
Read 2 more answers
A 15 m ladder with a mass of 51 kg is leaning against a frictionless wall, which makes an angle of 60 degrees with the horizonta
timofeeve [1]

Answer:

Explanation:

Given that, .

Mass of ladder is 51kg

Then, it weight is

WL = mg = 51 × 9.81 = 500.31N

This weight will act at the midpoint of the ladder

Length of ladder is 15m

The ladder makes an angle 55°C with the horizontal

An object whose mass is 81kg is at 4m from the bottom of the ladder

Then, weight of object

Wo = mg = 81 × 9.81 = 794.61 N

Using newton second law

Check attachment

Ng is normal force on the ground

Ff is the horizontal frictional force

Nw Is the normal force on the wall

ΣFy = 0

Ng = Wo + WL

Ng = 794.61 + 500.31

Ng = 1294.92 N

Also

ΣFx = 0

Ff — Nw = 0

Then,

Ff = Nw

Now taking moment about point A.

Check attachment

using the principle of equilibrium

Sum of clockwise moment equals to sum of anti-clockwise moment

Also note that the Normal force on the wall is not perpendicular to the ladder, so we will resolve that and also the weights of ladder and weight of object

Clockwise = Anticlockwise

Wo•Cos60 × 4 + WL•Cos60 × 7.5 = Nw•Sin60 × 15

794.61Cos60 × 4 + 500.31Cos60 × 7.5 = Nw × Sin60 × 15

1589.22 + 1876.163 = 12.99•Nw

3465.383 = 12.99•Nw

Nw = 3465.383 / 12.99

Nw = 266.77 N

Since, Nw = Ff

Then, Ff = 266.77N

the horizontal force exerted by the ground on the ladder is 266.77 N

8 0
3 years ago
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s = rΔθ

Using the equation for angular displacement, we can see that if two points have the same angular velocity and same angular acceleration, then they also have the same angular displacement.

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