Answer:
Height = 250km
Step-by-step explanation:
Given,
rate of rise of ballon 1 = 38 km/h
rate of rise of ballon 2 = 50 km/h
Let the time after which both the ballons will reach same height be 't'.
hence, after 't' hours,
⇒ height of ballon 1 = height of ballon 2
⇒ 38t + 60 = 50t
⇒ 12t = 60
⇒ t = 5 hours
so, the height at which both the ballons will be at the same height will be 250km.
4^m * 4^2 = 12
4^(m + 2) = 4^(log4 12)
m + 2 = log4 (12)
m = log4 (12) - 2.
15cm long
44
hundreds
