Answer:








Step-by-step explanation:
Given

Convert the probability to decimal

Solving (a): P(ABC)
This is calculated as:

This gives:


Solving (b): 
This is calculated as:

In probability:

So, we have:




Solving (c): 
This is calculated as:

![P(AB^cC) = P(A) * [1 - P(B)] * P(C)](https://tex.z-dn.net/?f=P%28AB%5EcC%29%20%3D%20P%28A%29%20%2A%20%5B1%20-%20P%28B%29%5D%20%2A%20P%28C%29)



Solving (d): 
This is calculated as:

![P(A^cBC) = [1-P(A)] *P(B) * P(C)](https://tex.z-dn.net/?f=P%28A%5EcBC%29%20%3D%20%5B1-P%28A%29%5D%20%2AP%28B%29%20%2A%20P%28C%29)



Solving (e): 
This is calculated as:

![P(AB^cC^c) = P(A) * [1-P(B)] * [1-P(C)]](https://tex.z-dn.net/?f=P%28AB%5EcC%5Ec%29%20%20%3D%20P%28A%29%20%2A%20%5B1-P%28B%29%5D%20%2A%20%5B1-P%28C%29%5D)
![P(AB^cC^c) = 0.48 * [1-0.48] * [1-0.48]](https://tex.z-dn.net/?f=P%28AB%5EcC%5Ec%29%20%20%3D%200.48%20%2A%20%5B1-0.48%5D%20%2A%20%5B1-0.48%5D)


Solving (f): 
This is calculated as:

![P(A^cBC^c) = [1-P(A)] * P(B) * [1-P(C)]](https://tex.z-dn.net/?f=P%28A%5EcBC%5Ec%29%20%20%20%3D%20%5B1-P%28A%29%5D%20%2A%20P%28B%29%20%2A%20%5B1-P%28C%29%5D)
![P(A^cBC^c) = [1-0.48] * 0.48 * [1-0.48]](https://tex.z-dn.net/?f=P%28A%5EcBC%5Ec%29%20%20%20%3D%20%5B1-0.48%5D%20%2A%200.48%20%2A%20%5B1-0.48%5D)


Solving (g): 
This is calculated as:

![P(A^cB^cC) = [1-P(A)] * [1-P(B)] * P(C)](https://tex.z-dn.net/?f=P%28A%5EcB%5EcC%29%20%20%3D%20%5B1-P%28A%29%5D%20%2A%20%5B1-P%28B%29%5D%20%2A%20P%28C%29)
![P(A^cB^cC) = [1-0.48] * [1-0.48] * 0.48](https://tex.z-dn.net/?f=P%28A%5EcB%5EcC%29%20%20%3D%20%5B1-0.48%5D%20%2A%20%5B1-0.48%5D%20%2A%200.48)


Solving (h): 
This is calculated as:

![P(A^cB^cC^c) = [1-P(A)] * [1-P(B)] * [1-P(C)]](https://tex.z-dn.net/?f=P%28A%5EcB%5EcC%5Ec%29%20%20%3D%20%5B1-P%28A%29%5D%20%2A%20%5B1-P%28B%29%5D%20%2A%20%5B1-P%28C%29%5D)
![P(A^cB^cC^c) = [1-0.48] * [1-0.48] * [1-0.48]](https://tex.z-dn.net/?f=P%28A%5EcB%5EcC%5Ec%29%20%20%3D%20%5B1-0.48%5D%20%2A%20%5B1-0.48%5D%20%2A%20%5B1-0.48%5D)


3 15/16. ( I hope you know how to write it)
Answer: if you have infinity points, which i will asume are the events, they cant have the same probability because then the probability will not be normalized, because in graph of prob vs variable, you will se infinite area under the curve if the probability is constant.
And yes, can all points have positive probability of occurring, but besides you medium value (the bell for example) you will see an asintotic decrease to the zero.
Answer:
The electrician has 14 feet of cable.