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4 years ago

The author’s feeling about a subject or topic, which is evidenced in word choice, is called __________.

Physics

2 answers:

True [87]4 years ago

6 0

The author’s feeling about a subject or topic, which is evidenced in word choice, is called tone.

MatroZZZ [7]4 years ago

5 0

The author’s feeling about a subject or topic, which is evidenced in word choice, is called tone. They could be literal meanings which are meanings explicitly given to the readers or the person being told to. In this type of meaning, the person doesn’t need to think the words too much or ponder on the meaning because they could easily understand what the other person or the author implies. Meanwhile connotative meanings are meanings using different figures of speech or symbolism that the person still needs to think it over before knowing the actual meaning of the word, sentence or story.

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Speed in any given direction is called A. Trust B.velocity C.mass D.acceleration

ahrayia [7]

B. velocity is the speed in any given direction.

7 0

3 years ago

Read 2 more answers

A uniform beam is suspended horizontally by two identical vertical springs that are attached between the ceiling and each end of

puteri [66]

The frequency and amplitude of the SHM beam is 0.8 Hz and 0.098 m. The frequency of the SHM wave when gravel falls is 0.8 Hz and the amplitude of subsequent SHM beam is 0.4m.

(a) Mass of the spring = 225 Kg

Mass of the sack = 175 Kg

Amplitude of the beam = 40 cm = 0.40 m

Frequency of the beam = F = 0.60 cycles/s

The formula for frequency of oscillation =

= f = (1/2π) X √(k/m)

where, k = 2π²F²m

= k = 2 X (3.14)² X 0.6² X (225 + 175)

= k = 5685.37 N/m

Strength of the spring before gravels fall = x =

= x = mg / k

= x = [ (225 + 175 ) X 9.8 ] / 5685.37

= x = 0.689 m

But, the spring is stretched by the distance of x' which is expressed as,

= X = x - x'

= X = 0.689 - 0.40

= X = 0.289 m

Now, since we know that the gravel falls, thus frequency = f =

= f = (1/2π) X √(k/m)

= f= (1/ 2 X 3.14) X √ 5685.37 / 225

= f = 0.8 Hz

(b) Assuming that the spring is stretched, x = mg/k =

= x = (225 X 9.8) / 5685.37

= x = 0.3878 m

Thus, the amplitude of the sack = A = 0.3878 - 0.289

= A = 0.098 m

= s = A X √(k/m)

= s = 0.4 X √(5685.37/400)

= s = 1.508 m/s

The frequency = f' =

= f' = (1/2π) X √(k/m)

= f' = (1/2 X 2.14) X √(5685.37/225)

= f' = 0.8 Hz

(d) New amplitude = A' =

= A' = 0.38 + 0.038 (after calculating the new distance)

= A' = 0.4 m

To know more about Spring:

brainly.com/question/15850235

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2 years ago

An airplane travels at 950 km/h. how long does it take to travel 1.00 km

Reptile [31]

First calculate the percentage of one hr it takes. You can do this by dividing the distance by the velocity. The general formula for this is:

$D = v *t$

always remember to make sure your units are the same.

so that's 1km by the 950km/h velocity.

1/950 = 0.0010526 hrs

Then multiply that answer by 3600 (the number of seconds in 1 hr) to find how many seconds this is.

0.0010526 * 3600 = 3.789 seconds

4 0

3 years ago

PLEASE HELP THIS IS SCIENCE

jeka94

It should be the second one

4 0

3 years ago

A series circuit has a capacitor of 0.25 × 10⁻⁶ F, a resistor of 5 × 10³ Ω, and an inductor of 1H. The initial charge on the cap

viktelen [127]

Answer:

$q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}$