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Lisa [10]
3 years ago
10

Electric power is to be generated by installing a hydraulic turbine–generator at a site 120 m below the free surface of a large

water reservoir that can supply water at a rate of 1500 kg/s steadily. Determine the power generation potential.
Physics
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

1764 kilowatt

Explanation:

h = 120 m, mass per second = 1500 kg/s

Power = m g h / t

Power = 1500 x 9.8 x 120 / 1

Power = 1764000 Watt

Power = 1764 kilowatt

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Choice E.

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A 10-cm-long spring is attached to theceiling. When a 2.0 kg mass is hung from it,the spring stretches to a length of 15 cm.a.Wh
alekssr [168]

(a) 392 N/m

Hook's law states that:

F=k\Delta x (1)

where

F is the force exerted on the spring

k is the spring constant

\Delta x is the stretching/compression of the spring

In this problem:

- The force exerted on the spring is equal to the weight of the block attached to the spring:

F=mg=(2.0 kg)(9.8 m/s^2)=19.6 N

- The stretching of the spring is

\Delta x=15 cm-10 cm=5 cm=0.05 m

Solving eq.(1) for k, we find the spring constant:

k=\frac{F}{\Delta x}=\frac{19.6 N}{0.05 m}=392 N/m

(b) 17.5 cm

If a block of m = 3.0 kg is attached to the spring, the new force applied is

F=mg=(3.0 kg)(9.8 m/s^2)=29.4 N

And so, the stretch of the spring is

\Delta x=\frac{F}{k}=\frac{29.4 N}{392 N/m}=0.075 m=7.5 cm

And since the initial lenght of the spring is

x_0 = 10 cm

The final length will be

x_f = x_0 +\Delta x=10 cm+7.5 cm=17.5 cm

8 0
3 years ago
Read 2 more answers
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Alex Ar [27]
The correct answer is B. 6 protons and 8 neutrons

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