Answer:
NaOH is the limiting reactant.
Explanation:
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In this case, since the reaction taking place between sodium hydroxide and chlorine has is:
Which must be balanced according to the law of conservation of mass:
Whereas there is a 2:1 mole ratio of NaOH to Cl2, which means that the moles of the former that are consumed by 0.85 moles of the latter are:
Therefore, since we just have 1.23 moles out of 1.70 moles of NaOH, we infer this is the limiting reactant.
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Answer:
47 protons, 62 neutrons, 47 electrons
Answer:
Ammonium nitrate is NH4NO3
iron(II) sulfate is FeSO4
magnesium hydroxide is MG(OH)2
titanium(II) chloride is TiCI2
cobalt(III) oxide is Co2O3
potassium sulfide is K2S
Barium acetate is C4H6BaO4
magnesium bromide is MgBr2
lithium carbonate is Li2CO3
potassium permanganate is KMnO4
Answer:
290.82g
Explanation:
The equation for the reaction is given below:
2Al + 3H2SO4 -> Al2(SO4)3 + 3H2 now, let us obtain the masses of H2SO4 and Al2(SO4)3 from the balanced equation. This is illustrated below:
Molar Mass of H2SO4 = (2x1) + 32 + (16x4) = 2 + 32 +64 = 98g/mol
Mass of H2SO4 from the balanced equation = 3 x 98 = 294g
Molar Mass of Al2(SO4)3 = (2x27) + 3[32 + (16x4)]
= 54 + 3[32 + 64]
= 54 + 3[96] = 54 + 288 = 342g
Now, we can obtain the mass of aluminium sulphate formed by doing the following:
From the equation above:
294g of H2SO4 produced 342g of Al2(SO4)3.
Therefore, 250g of H2SO4 will produce = (250 x 342)/294 = 290.82g of Al(SO4)3
Therefore, 290.82g of aluminium sulphate (Al(SO4)3) is formed.
isotopes have the same atomic number because they are the same element but have a different atomic mass because they contain a different number of neutrons.
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