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Luda [366]
2 years ago
13

How would the model and answer in the example problem change if Felicia lives 7··10mile from the soccer

Mathematics
1 answer:
sleet_krkn [62]2 years ago
7 0
Okay w sI suede your would multiple them and get 70bhjbbb 70 would ok she the answer
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Evaluate -4a + 10 when a = -2
stiks02 [169]

Answer:

<u>18</u>

Step-by-step explanation:

<em>replace a with -2</em>

-4(-2) + 10

<em>multiply the -4 and the -2, the negatives cancel out and leave you with 8</em>

8 +10

<em>just add</em>

18

4 0
3 years ago
Please help 10 points and brainliest picture attached
Setler79 [48]

Answer:

x=19/4 , y=3/4

Step-by-step explanation:

7 0
3 years ago
Solve for the unknown.
kenny6666 [7]

Based on the balance sheet of Company MSK, we can find the unknown amount of Net Income (loss) to be $18,843.

<h3>What is the Net Income (loss)?</h3>

The Assets as at 2021 should be equal to the sum of liabilities and equity.

The Equity is:

= Issued stocks + Net income - Dividends

The missing figure is therefore:

35,564 = 15,721 + 1,400 + Net Income - 400

Net Income = 35,564 + 400 - 15,721 - 1,400

= $18,843

Find out more on the Net Income at brainly.com/question/20598931.

#SPJ1

8 0
2 years ago
4. Find the standard from of the equation of a hyperbola whose foci are (-1,2), (5,2) and its vertices are end points of the dia
Ad libitum [116K]

The <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

<h3>How to find the standard equation of a hyperbola</h3>

In this problem we must determine the equation of the hyperbola in its <em>standard</em> form from the coordinates of the foci and a <em>general</em> equation of a circle. Based on the location of the foci, we see that the axis of symmetry of the hyperbola is parallel to the x-axis. Besides, the center of the hyperbola is the midpoint of the line segment with the foci as endpoints:

(h, k) = 0.5 · (- 1, 2) + 0.5 · (5, 2)

(h, k) = (2, 2)

To determine whether it is possible that the vertices are endpoints of the diameter of the circle, we proceed to modify the <em>general</em> equation of the circle into its <em>standard</em> form.

If the vertices of the hyperbola are endpoints of the diameter of the circle, then the center of the circle must be the midpoint of the line segment. By algebra we find that:

x² + y² - 4 · x - 4 · y + 4= 0​

(x² - 4 · x + 4) + (y² - 4 · y + 4) = 4

(x - 2)² + (y - 2)² = 2²

The center of the circle is the midpoint of the line segment. Now we proceed to determine the vertices of the hyperbola:

V₁(x, y) = (0, 2), V₂(x, y) = (4, 2)

And the distance from the center to any of the vertices is 2 (<em>semi-major</em> distance, a) and the semi-minor distance is:

b = √(c² - a²)

b = √(3² - 2²)

b = √5

Therefore, the <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

To learn more on hyperbolae: brainly.com/question/27799190

#SPJ1

5 0
1 year ago
What’s 3 times 72 in expanded Form?
Dominik [7]

200+ 10 + 6= 216

...........................................

4 0
3 years ago
Read 2 more answers
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