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Nookie1986 [14]
4 years ago
6

In this exercise, we estimate the rate at which the total personal income is rising in a metropolitan area. In 1999, the populat

ion of this area was 963,200, and the population was increasing at roughly 9300 people per year. The average annual income was $33,162 per capita, and this average was increasing at about $1300 per year (a little above the national average of about $1225 yearly). Use the Product Rule and these figures to estimate the rate at which total personal income was rising in the area in 1999. (Round your answer to three decimal places.)
Mathematics
1 answer:
Gnom [1K]4 years ago
8 0

Answer:

4.923%

Step-by-step explanation:

<u>Population in 1999 </u>

963,200

<u>Average annual income </u>

$33,162 per capita

<u>Total personal income</u>

963,200* 33,162 = $31,941,638,400

<u>Population in 2000 </u>

963,200+9,300= 972,500

<u>Average annual income </u>

$33,162+ $1,300 =$34,462  per capita

<u>Total personal income </u>

972,500* 34,462 = $33,514,295,000

<em>We must now find a number x such that  31,941,638,400 increased x% equals 33,514,295,000 . </em>That is to say<em>,</em>

31,941,638,400*(1+x/100)= 33,514,295,000

Isolating x we have

x = 4.923%

And the rate at which total personal income was rising in the area in 1999 was 4.923%

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