For this case we have that by definition, an equation of the line of the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have two points through which the line passes, then we find the slope:
Then, the equation is of the form:
We substitute a point and find b:
Finally we have:
y = x-4
Answer:
Option B
Answer:
34.01% probability that his score is at least 532.1.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If 1 of the men is randomly selected, find the probability that his score is at least 532.1.
This is 1 subtracted by the pvalue of Z when X = 532.1. So
has a pvalue of 0.6591
1 - 0.6591 = 0.3409
34.01% probability that his score is at least 532.1.
Answer:
The critical value for this hypothesis test is 6.571.
Step-by-step explanation:
In this case the professor wants to determine whether the average number of minutes that a student needs to complete a statistics exam has a standard deviation that is less than 5.0 minutes.
Then the variance will be,
The hypothesis to determine whether the population variance is less than 25.0 minutes or not, is:
<em>H</em>₀: The population variance is not less than 25.0 minutes, i.e. <em>σ²</em> = 25.
<em>Hₐ</em>: The population variance is less than 25.0 minutes, i.e. <em>σ²</em> < 25.
The test statistics is:
The decision rule is:
If the calculated value of the test statistic is less than the critical value, then the null hypothesis will be rejected.
Compute the critical value as follows:
*Use a chi-square table.
Thus, the critical value for this hypothesis test is 6.571.
