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Sati [7]
3 years ago
14

A block of wood 3.0 cm on each side and has a mass of 27 g. What is the density of this block.

Mathematics
1 answer:
Sidana [21]3 years ago
8 0
The density is 1g/cm³. To calculate density, the equation density=mass/volume is used. You already know the mass, 27g, but you need the volume. The equation for volume is length x width x height. Plug in your side measure 3, to get 3 x 3 x 3, which is 27cm³. Now, just divide the mass by the volume. 27g/27cm³= 1g/cm³
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Answer:

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Step-by-step explanation:

21x-18x+28xy

3x+28xy

x(3+28y)

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Step-by-step explanation:

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Solve the system: <br> 2/x - 3/y =-5; 4/x + 6\y =14
sertanlavr [38]

The solution is x = 2 \text{ and } y = \frac{1}{2}

<em><u>Solution:</u></em>

Let us assume,

a = \frac{1}{x}\\\\b = \frac{1}{y}

<em><u>Given system of equations are:</u></em>

\frac{2}{x} - \frac{3}{y} = -5

\frac{4}{x} + \frac{6}{y} = 14

<em><u>Rewrite the equation using "a" and "b"</u></em>

2a - 3b = -5 ------------ eqn 1

4a + 6b = 14 -------------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 1 by 2</u></em>

2(2a - 3b = -5)

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<em><u>Add eqn 2 and eqn 3</u></em>

4a + 6b = 14

4a - 6b = -10

( - ) --------------------

8a = 4

a = \frac{4}{8}\\\\a = \frac{1}{2}

Substitute a = 1/2 in eqn 1

2(\frac{1}{2}) -3b = -5\\\\1 - 3b = -5\\\\3b = 6\\\\b = 2

Now let us go back to our assumed values

Substitute a = 1/2 in assumed values

a = \frac{1}{x}\\\\\frac{1}{2} = \frac{1}{x}\\\\x = 2

Substitute b = 2 in assumed value

b = \frac{1}{y}\\\\2 = \frac{1}{y}\\\\y = \frac{1}{2}

Thus the solution is x = 2 \text{ and } y = \frac{1}{2}

3 0
2 years ago
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drek231 [11]

Answer:

No

Step-by-step explanation:

The lines arent equal

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