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notka56 [123]
3 years ago
11

What is the solution of log6x + log6(x + 5) = 2?

Mathematics
2 answers:
umka2103 [35]3 years ago
7 0

Answer:

The answer is 4 on EDGE 2020

AlekseyPX3 years ago
6 0

Answer: the answer is - 15-5√13 / 6

Step-by-step explanation:

X= 15-5√13  

  -  -------------

         6

hope you got it

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Barbara can pay either $80 per month or one lump sum of $800 per year for car insurance. How much does she save yearly if she ch
Schach [20]

Answer:

$160

Step-by-step explanation:

In the monthly payment option she would pay $80 per month, therefore in a year (12 months) she would pay:

$80*12 =  $960

We can see that this amount is greater than the $800 she would pay in the lump sum payment option.

The money she would save is:

$960 - $800 = $160

She would save<u> $160 yearly</u> with the lump sum payment option.

4 0
3 years ago
Pls help with a good explanation and show ur work will give brainleiest
lyudmila [28]
From the graph: there are 200 students overall. For the next 100, we can divide each number by 2 to find an estimate for how many with participate in MATH tutoring. 40 divided by 2 =20 students participating in MATH tutoring.

Part B- There are currently 55 students out of 200 in SCIENCE tutoring. We add 55 more for 400 = 110, add 55 more for 600=165, and then add half of 55 (27.5 or 28 because you CANNOT have half a student) for 700 students total. 55+55+55+28=193 students.
7 0
3 years ago
Solution or no solution?
NikAS [45]
I think the answer is solution
8 0
3 years ago
Which point is a solution to y&lt;4x+5
Alla [95]

Answer:

(1,-1)

Step-by-step explanation:

y < 4x+5

x = 1, y = -1 => -1 < -4+5 (T)

3 0
3 years ago
A box contains 10 tags, numbered 1 through 10, with a different number on each tag. A second box contains 8 tags, numbered 20 th
blagie [28]

Answer:

E) 29.0

Step-by-step explanation:

The value of the sum is obtained from 2 independent experiments: the value of the number of the first box X₁ and the value of the number of the second box X₂.

The expected value of a draw is the average of all its values, so E(X₁) = (1+2+3+4+5+6+7+8+9+10)/10 = 5.5 and E(X₂) = (20+21+22+23+24+25+26+27)/8 = 23.5

Hence, E(X₁+X₂) = E(X₁)+E(X₂) = 5.5+23.5=29

3 0
3 years ago
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