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3 years ago

(6x3 + 3x² + 3) + (2x - 5x + 1) the sum is?

Mathematics

2 answers:

laiz [17]3 years ago

8 0

<h2>Answer:</h2><h2><em><u>8x^3 + 3x^2 - 5x + 4 is the answer.</u></em></h2>

Step-by-step explanation:

(6x^3 + 3x² + 3) + (2x^3 - 5x + 1)

6x^3 + 2x^3 = 8x^3

3x^2 + 0 = 3x^2

-5x + 0 = -5x

3 + 1 = 4

8x^3 + 3x^2 - 5x + 4 is the answer because you have to put all the terms that were solved together. This will lead to 8x^3 + 3x^2 - 5x + 4. And, standard form is ax^2 + bx + c. So, 8x^3 + 3x^2 - 5x + 4 is the answer.

Hope this helped,

Kavitha

Licemer1 [7]3 years ago

3 0

Answer:

= 8x³ + 3x² - 5x + 4

Step-by-step explanation:

(6x³ + 3x² + 3) + (2x³ - 5x + 1)

= 6x³ + 3x² + 3 + 2x³ - 5x + 1 remove parentheses

= 6x³ + 2x³ + 3x² - 5x + 1 group like terms

= 8x³ + 3x² - 5x + 3 + 1 add similar elements

= 8x³ + 3x² - 5x + 4

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3 years ago

How do you solve 9| x+8 | + 10 < 55 & how is it graphed

mafiozo [28]

Hello!

First, let's write the problem.
$9\left|x+8\right|+10\ \textless \ 55|x+8|+10\ \textless \ 55$
Subtract 10 from both sides.
$9\left|x+8\right|+10-10\ \textless \ 55-10$
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Divide both sides by 9.
$\frac{9\left|x+8\right|}{9}\ \textless \ \frac{45}{9}$
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When we got absolute value, we are going to get two results.
$x+8\ \textless \ 5$
and
$x+8\ \textgreater \ -5$

Let's solve the first one,
$x+8\ \textless \ 5x+8\ \textless \ 5$
Subtract 8 from both sides.
$x+8-8\ \textless \ 5-8$
$x\ \textless \ -3x\ \textless \ -3$

Let's solve the second one.
$x+8\ \textgreater \ -5$
Subtract 8 from both sides.
$x+8-8\ \textgreater \ -5-8$
$x\ \textgreater \ -13x\ \textgreater \ -13$

Let's combine the ranges.
$-13\ \textless \ x\ \textless \ -3$

The attachment shows how would you graph it.
You can feel free to let me know if you have any questions regarding this.
Thanks!

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3 years ago

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Answer: it’s B

Step-by-step explanation:

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2 years ago