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3 years ago

(6x3 + 3x² + 3) + (2x - 5x + 1) the sum is?

Mathematics

2 answers:

laiz [17]3 years ago

8 0

<h2>Answer:</h2><h2><em><u>8x^3 + 3x^2 - 5x + 4 is the answer.</u></em></h2>

Step-by-step explanation:

(6x^3 + 3x² + 3) + (2x^3 - 5x + 1)

6x^3 + 2x^3 = 8x^3

3x^2 + 0 = 3x^2

-5x + 0 = -5x

3 + 1 = 4

8x^3 + 3x^2 - 5x + 4 is the answer because you have to put all the terms that were solved together. This will lead to 8x^3 + 3x^2 - 5x + 4. And, standard form is ax^2 + bx + c. So, 8x^3 + 3x^2 - 5x + 4 is the answer.

Hope this helped,

Kavitha

Licemer1 [7]3 years ago

3 0

Answer:

= 8x³ + 3x² - 5x + 4

Step-by-step explanation:

(6x³ + 3x² + 3) + (2x³ - 5x + 1)

= 6x³ + 3x² + 3 + 2x³ - 5x + 1 remove parentheses

= 6x³ + 2x³ + 3x² - 5x + 1 group like terms

= 8x³ + 3x² - 5x + 3 + 1 add similar elements

= 8x³ + 3x² - 5x + 4

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3 years ago

Kenneth drove 184.25 miles in 3 7/20 hours. What was his average speed?

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4 years ago

Suppose that the annual rainfall in Ferndale, California, is known to be normally distributed, with a mean of 35.5 inches and a

erastovalidia [21]

The average annual rainfall will be more than 40.6 inches in about 2.1 percent of the years.

<h3>What is the average annual rainfall?</h3>

Generally, the equation for the probability is mathematically given as

$P( X < x) = p( Z < x - \mu / \sigma)$

Therefore

$P( X > x) = 0.021$

$P( X < x ) = 1 - 0.021\\\\\p( X < x) = 0.979$

$P( Z < x - \mu / \sigma) = 0.979$

The z score for the probability of 0.979 is 2.034, according to the table of z values.

$x - \mu / \sigma \\\\x= 2.034$

In the given equation, replace the values of mu and sigma with their respective values, and then solve for x.

$x - 35.5 / 2.5 \\x= 2.034$

In conclusion, The average annual rainfall will be more than 40.6 inches in about 2.1 percent of the years.