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Katarina [22]
3 years ago
8

What is the factored form of the polynomial 3x-3y

Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0

Answer:

Step-by-step explanation:

3x - 3y = 3(x-y)

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Pleaseee help this is urgent!!! I need it in English! Please show all the work ! 14 points
zzz [600]

Answer:

width = 40 feet, length = 90 feet

Step-by-step explanation:

length = 2w + 10

width = w

Perimeter = 260

Perimeter of rectangle = 2length + 2width

Sub the values into that equation:

260 = 2(2w + 10) + 2(w)

260 = 4w + 20 + 2w

260 = 6w + 20

260 - 20 = 6w

240 = 6w

w = 240/6

w = 40

So now we know the width of the garden is 40 feet.

To find the length, substitute the width into the length equation:

length = 2w + 10

length = 2(40) + 10

length = 90 feet

length = 90 feet, width = 40 feet

3 0
3 years ago
Which inverse operation would be used to verify the following equation?
DochEvi [55]
You would bring the division over to to other side. When we switch it to the other side, it turns into a multiplication (the opposite of division). So we go from:

102 / 3 = 34
to
102 = 34 * 3

Which is C for your multiple choice! :)
7 0
3 years ago
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SOMEONE HELP ASAPPPP PLEASEEE,PLEASE EXPLAIN HOW U GOT YOUR ANSWER, I NEED AN EXPLANATION IN ORDER TO COMPLETE THIS! NO LINKS OR
sleet_krkn [62]

Answer:

x = 2.8 units

Step-by-step explanation:

volume = width x length x height

23.52 = 1.5 x 5.6 x height

height = 23.52/(1.5 x 5.6) = 23.52/8.4 = 2.8 units

6 0
2 years ago
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solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
Hey yall i need help again im just lazy but will mark brainlyest
ElenaW [278]

Answer:  1=1 question 2 = 1 again 5-6 is the next and 4 3-10  5-6 next answer2-7  3-8 5-4 -22--9 2-29 are all the answers

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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