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Masteriza [31]
2 years ago
14

What properties would you expect to be different for the two enantiomers of 2-pentanol?

Chemistry
1 answer:
-BARSIC- [3]2 years ago
5 0

Answer: direction of rotation of plane polarized light and reaction with chiral reagents.

Explanation:

Enantiomers are stereoisimers which are mirror images of each other. They possess the same physical and chemical properties except that the direction of rotation of plane polarized light and reaction with chiral reagents. (+)-2-pentanol will rotate plane polarized light to the right and react with dextrorotatory enantiomers of chiral reagents while (-)-2-pentanol will rotate plane polarized light to the left and react with leavorotatory enantiomers of chiral reagents.

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This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): An analytical chemist has det
jeyben [28]

Answer:

0.054 mol O

Explanation:

<em>This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): CH₃CO₂H. An analytical chemist has determined by measurements that there are 0.054 moles of carbon in a sample of acetic acid. How many moles of oxygen are in the sample?</em>

<em />

Step 1: Given data

  • Chemical formula of acetic acid: CH₃CO₂H
  • Moles of carbon in the sample: 0.054 moles

Step 2: Establish the appropriate molar ratio

According to the chemical formula, the molar ratio of C to O is 2:2.

Step 3: Calculate the moles of oxygen in the sample

We will use the molar ratio to determine the moles of oxygen accompanying 0.054 moles of carbon.

0.054 mol C × (2 mol O/2 mol C) = 0.054 mol O

6 0
3 years ago
The equilibrium constant, Kc, for the following reaction is 3.61×10-4 at 426 K. PCl5(g) PCl3(g) + Cl2(g) When a sufficiently lar
iogann1982 [59]

Answer:

the concentration of PCl5 in the equilibrium mixture = 296.20M

Explanation:

The concept of equilibrium constant was applied where the equilibrium constant is the ration of the concentration of the product over the concentration of the reactants raised to the power of their coefficients. it can be in terms of concentration in M or in terms of Pressure in atm.

The detaied steps is as shown in the attached file.

8 0
2 years ago
*
Murrr4er [49]

The answer fam is......... False

7 0
3 years ago
If the percent yield for the following reaction is 75.0%, and 25.0 g of NO₂ are consumed in the reaction, how many grams of nitr
victus00 [196]

Answer:

17.1195 grams of nitric acid are produced.

Explanation:

3NO_2+H_2O\rightarrow 2HNO_3+NO

Moles of nitrogen dioxide :

\frac{25.0 g}{56 g/mol}=0.5434 mol

According to reaction 3 moles of nitrogen dioxides gives 2 moles of nitric acid.

Then 0.5434 moles of nitrogen dioxides will give:

\frac{2}{3}\times 0.5434 mol=0.3623 mol of nitric acid.

Mass of 0.3623 moles of nitric acid :

0.3623 mol\times 63 g/mol=22.8260 g

Theoretical yield = 22.8260 g

Experimental yield = ?

\%Yield=\frac{\text{Experimental yield}}{\text{theoretical yield}}\times 100

75\%=\frac{\text{Experimental yield}}{22.8260 g}

Experimental yield of nitric acid = 17.1195 g

7 0
3 years ago
Question
andreev551 [17]

Answer:

Sln

n=m/mr

n=25/100

n=0.25mole of Caco3

Malality =number of moles/volume (divided by number of moles both sides)

volume =Malality /number of moles

v=0.125/0.25

v=0.500L

I hope this help

5 0
2 years ago
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