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Bumek [7]
2 years ago
12

Calculate the moles of calcium oxalate formed from 5 grams of potassium oxalate (molar mass 184.24 g/mol) the mole mole ratio fr

om the balanced equation is 2.1 potassium oxalate to calcium oxalate
Chemistry
1 answer:
Nataly_w [17]2 years ago
7 0

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).

We can calculate the moles of CaC₂O₄ obtained considering the following relationships.

  • The molar mass of K₂C₂O₄ is 184.24 g/mol.
  • The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.

5 g K_2C_2O_4 \times \frac{1molK_2C_2O_4}{184.24gK_2C_2O_4}  \times \frac{1molCaC_2O_4}{2molK_2C_2O_4} = 0.03molCaC_2O_4

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Learn more: brainly.com/question/15288923

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From the graph shown, 
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6 0
3 years ago
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7 0
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Explain how scientific observations led to the development of, and changes to, the periodic table.
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Dvinal [7]

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5 0
3 years ago
Calculate the mass of ammonia (NH3) that contains a billion (1.00 * 10^12) hydrogen atoms.
Lynna [10]

Answer:

The mass of ammonia (NH3) that contains 1.00 \times 10^12 hydrogen atoms is 9.4\times 10^{-12} g.

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