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Rus_ich [418]
3 years ago
7

Penelope drove 27 kilometers. Which expression finds the distance she drove in centimeters? Use the metric table to help answer

the question. Metric Table kilo- hecto- deka- unit deci- centi- milli- 1,000 100 10 1 0.1 0.01 0.001 StartFraction 27 times 1,000,000 EndFraction 27 divided by 100,000 27 divided by 1,000,000 StartFraction 27 times 100,000 EndFraction please help asap!!! brainliest for HONEST ANSWER NO COPYING OR SEARCHING and most importantly stay safe!!!
Mathematics
2 answers:
mel-nik [20]3 years ago
8 0

Answer:

27x 100,000 have a good day

vovikov84 [41]3 years ago
4 0

Answer:

Step-by-step explanation:

1km=1000 m

1 m=100 cm

1 km=1000×100=100000 cm

27 km=100000×27=2,7 00,000 cms

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Which of the ratios below is equivalent to 5:2? Select all that apply.
Hoochie [10]

Answer:

D) 10:4

Step-by-step explanation:

mark me brainliest please

3 0
3 years ago
Read 2 more answers
The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of 10 batteries
Nat2105 [25]

Answer:

(1) We are conducting the one-sample t-test and will be testing for the hypothesis of mean battery greater than 25 h. So, we will reject the null hypothesis for mean battery life equal to 25 hr against the alternative hypothesis for mean battery life greater than 25 hr.

(2) A 95% lower confidence interval on mean battery life is 25.06 hr.

Step-by-step explanation:

We are given that a random sample of 10 batteries is subjected to an accelerated life test by running them continuously at an elevated temperature until failure, and the following lifetimes (in hours) are obtained: 25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                              P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~  t_n_-_1

where, \bar X = sample mean BAC = \frac{\sum X}{n} = 26 hr

             s = sample standard deviation = \sqrt{\frac{\sum(X - \bar X)^{2} }{n-1} } = 1.625 hr

             n = sample of batteries = 10

             \mu = population mean battery life

<em> Here for constructing a 95% lower confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

(1) It is stated that the manufacturer wants to be certain that the mean battery life exceeds 25 h.

Since we are conducting the one-sample t-test and will be testing for the hypothesis of mean battery greater than 25 h. So, we will reject the null hypothesis for mean battery life equal to 25 hr against the alternative hypothesis for mean battery life greater than 25 hr.

(2) So, a 95% lower confidence interval for the population mean, \mu is;

P(-1.833 < t_9) = 0.95  {As the lower critical value of t at 9

                                             degrees of  freedom is -1.833 with P = 5%}    

P(-1.833 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }) = 0.95

P( -1.833 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} ) = 0.95

P( \bar X-1.833 \times {\frac{s}{\sqrt{n} } } < \mu) = 0.95

<u>95% lower confidence interval for</u> \mu = [ \bar X-1.833 \times {\frac{s}{\sqrt{n} } } ]

                                                             = [ 26-1.833 \times {\frac{1.625}{\sqrt{10} } } ]

                                                            = [25.06 hr]

Therefore, a 95% lower confidence interval on mean battery life is 25.06 hr.

5 0
3 years ago
Area= 18yd squared, length= 6yd<br> width=
GenaCL600 [577]

Answer:

The width is 3 yds

Step-by-step explanation:

Area = length * width

18 = 6*w

Divide each side by 6

18/6 = 6w/6

3=w

The width is 3 yds

7 0
3 years ago
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VMariaS [17]

Answer:

ok so the first one is

1200x+2000

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b.4000

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a.5600

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a. 6800

b. 7000

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b. 8000

They would equal out at 8000 in month 5

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3 years ago
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zepelin [54]
What diagram can you add a picture of it ?
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