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3 years ago

F(x)=x^2-10 and g(x)=7–x, find (f-g)(-6)

1 answer:

3 0

$(f-g)(x)=f(x)-g(x)\\\\f(x)=x^2-10\\\\f(-6)\to\text{put x = -6 to the equation}\\\\f(-6)=(-6)^2-10=36-10=26\\\\g(x)=7-x\\\\g(-6)\to\text{put x = -6 to the equation}\\\\g(-6)=7-(-6)=7+6=13\\\\(f-g)(-6)=f(-6)-g(-6)=26-13=13$

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3 years ago

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pashok25 [27]

Count what fraction receive Karen, James and Frank in total:

since

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then $\frac{1}{8} +\frac{2}{8} +\frac{3}{8} =\frac{1+2+3}{8}=\frac{6}{8} =\frac{2\cdot 3}{2\cdot 4} =\frac{3}{4}$ .

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