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3 years ago

The volume of water in a transfer pipette is 15.23 ml. A 6.7 mL

Chemistry

1 answer:

Alja [10]3 years ago

3 0

Given :

Volume of water in a transfer pipette is 15.23 ml.

A 6.7 ml volume of water was then transferred out.

To Find :

The new volume.

Solution :

Initial volume , $V_i=15.23\ ml$ .

Volume removed out , v = 6.7 ml .

Let, new volume be $V_f$ .

Now , new volume = Initial volume - Volume removed out .

$V_f=V_i-v\\\\V_f=15.23-6.7\\\\ V_f=8.5\ ml$

Therefore, new volume is 8.5 ml.

Hence, this is the required solution.

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dusya [7]

Answer:

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Explanation:

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3 years ago

A small container of perfume is opened in a classroom. Soon every student in the room smells the perfume. Explain this in terms

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3 years ago

Chemistry student needs of 55g acetone for an experiment. by consulting the crc handbook of chemistry and physics, the student d

sergeinik [125]

Answer:

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Volume = ?

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Volume = Mass ÷ Density

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3 years ago

Which of these statements about the conservation of mass is not correct?

Verdich [7]

B
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3 years ago

4) What volume will the gas in the balloon at right occupy at 250k?<br><br> balloon: 4.3L 350K

swat32

Answer:

2.87 liter.

Explanation:

Given:

Initially volume of balloon = 4.3 liter

Initially temperature of balloon = 350 K

Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

$Pv =nRT$

Assuming pressure as constant,

V∝ T

Now, let K is the constant.

V = KT

Let initial volume of balloon , $V_{1}$ = 4.3 liter

1000 liter = 1 meter cube

1 liter = $\frac{1}{1000} m^{3} = 10^{-3} m^{3$

4.3 liter = $4.3\times10^{-3}=4.3\times10^{-3} m^{3}$

And initial temperature of balloon, $T_{1}$ = 350 K

Let the final volume of balloon is $V_{2}$

And as given, final temperature of balloon, $T_{2}$ is 250 K

Now, $V_{1} = KT_{1}$

$4.3\times10^{-3}=K\times350\ (equation\ 1 )$

$V_{2} = KT_{2}$

$=K\times250\ (equation 2)$

Dividing equation 1 and 2,

$\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}$

K cancelled by K.

By cross multiplication:

$350V_{2} =4.3\times10^{-3} \times250\\V_{2} =\frac{ 4.3\times10^{-3} \times250\\}{350} \\ = \frac{1075\times10^{-3}}{350} \\ =2.87\times10^{-3}m^{3}$

Now, convert it into liter with the help of calculation done above,

$2.87\times10^{-3} \times1000\\2.87\times10^{-3} \times10^{3} \\2.87\ liter$

Therefore, volume of the gas in the balloon at 250 K will be 2.87 liter.

4 0

4 years ago