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Flauer [41]
3 years ago
7

How many C-13 atoms are present, on average, in a 1.6000×104-atom sample of carbon?

Chemistry
2 answers:
Marrrta [24]3 years ago
7 0
<h3><u>Answer;</u></h3>

= 171 atoms of C-13

<h3><u>Explanation;</u></h3>
  • Carbon has two naturally occurring isotopes: C-12, whose natural abundance is 98.93% and C-13  whose natural abundance is 1.07%.
  • Therefore, the number of C-13 atoms sample of 1.6000×10^4 atoms of carbon will be;

          = (1.6000×10^4 × 1.07 %)/100%

           = 171.2

           ≈ 171  atoms

san4es73 [151]3 years ago
5 0
I don't know why I am answering this question but assuming C-13 has a natural abundance of 1.07%:

(1.6000x10^4)(0.0107) = 171.2 = 171 atoms of C-13
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