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Flauer [41]
3 years ago
7

How many C-13 atoms are present, on average, in a 1.6000×104-atom sample of carbon?

Chemistry
2 answers:
Marrrta [24]3 years ago
7 0
<h3><u>Answer;</u></h3>

= 171 atoms of C-13

<h3><u>Explanation;</u></h3>
  • Carbon has two naturally occurring isotopes: C-12, whose natural abundance is 98.93% and C-13  whose natural abundance is 1.07%.
  • Therefore, the number of C-13 atoms sample of 1.6000×10^4 atoms of carbon will be;

          = (1.6000×10^4 × 1.07 %)/100%

           = 171.2

           ≈ 171  atoms

san4es73 [151]3 years ago
5 0
I don't know why I am answering this question but assuming C-13 has a natural abundance of 1.07%:

(1.6000x10^4)(0.0107) = 171.2 = 171 atoms of C-13
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Answer:

It is pseudoscience because there are at least 118 known elements in nature.

Explanation:

Alchemy is an ancient branch of natural philosophy (not used much anymore).

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4 0
3 years ago
Consider the following reaction where K. = 9.52 10 2 at 350 K.
Harman [31]

Answer:

The correct answer is A :))

3 0
3 years ago
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MAVERICK [17]

Answer:

C

Explanation:

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4 0
3 years ago
2. A sample of neon gas has a volume of 87.6 L at STP. How many moles are present?
PSYCHO15rus [73]

Answer:

                      3.91 moles of Neon

Explanation:

According to Avogadro's Law, same volume of any gas at standard temperature (273.15 K or O °C) and pressure (1 atm) will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

                 n = moles = <u>???</u>

                 V = Volume = 87.6 L

Solution:

               As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

                          = ( 1 mole × 87.6 L) ÷ 22.4 L

                          = 3.91 moles

<h3>2nd Method:</h3>

                     Assuming that the gas is acting ideally, hence, applying ideal gas equation.

                              P V  =  n R T      ∴  R  =  0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹

Solving for n,

                              n  =  P V / R T

Putting values,

                              n  =  (1 atm × 87.6 L)/(0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹ × 273.15K)

                              n  =  3.91 moles

Result:

          87.6 L of Neon gas will contain 3.91 moles at standard temperature and pressure.

7 0
3 years ago
Plastics are synthetic, organic polymers. how are plastics similar and different to polysaccharides
yawa3891 [41]
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6 0
3 years ago
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